All categories

2 years ago

Calculate the length of ed and be

Mathematics

1 answer:

pashok25 [27]2 years ago

4 0

Answer:

ED = 6.5 cm

BE = 14.4 cm

Step-by-step explanation

AB/BC = AE/ED is less than or eqauls ED = BC×AE/AB

ED = 5×26/20 = 130/20 = 6.5 cm

and

AB/AC = BE/CD => BE = AB×CD/AC

BE = 20×18/25 = 360/25 = 14.4 cm

You might be interested in

Help I’m being timed!!

UNO [17]

Answer:

False the radius would be 6.5

Step-by-step explanation:

Hope this Helps! :)

5 0

3 years ago

PLEASE HELP!!!!!

seraphim [82]

Answer:

2,5,6,15

Step-by-step explanation:

that's what I think

6 0

3 years ago

Find: (6m5 3 â€"" m3 â€"" 4m) â€"" (â€""m5 2m3 â€"" 4m 6) Write subtraction of a polynomial expression as addition of the additi

aliina [53]

The subtraction in the standard form of the polynomial is $\rm 7m^5-3m^2-3$ .

Given that

Expression; $\rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6)$ .

We have to determine

The subtraction of a polynomial.

According to the question

Expression; $\rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6)$ .

To find the subtraction of the polynomial follow all the steps given below.

Step1; Write the expression as an additive inverse.

$\rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6)\\\\\rm (6m^5 + 3 - m^3 -4m) +(m^5 -2m^3 +4m - 6)$

Step2; Rewrite terms that are subtracted as the addition of the opposite.

$\rm (6m^5 + 3 - m^3 -4m) +(m^5 -2m^3 +4m - 6)\\\\6m^5 + 3 + (-m^3) + (-4m) + m^5 + (2m^3) + 4m + (-6)$

Step3; Group-like terms.

$\rm 6m^5 + 3 + (-m^3) + (-4m) + m^5 + (2m^3) + 4m + (-6)\\\\(6m^5 + m^5) + [3 + (-6)] + [(-m^3) + (-2m^3)] + [(-4m) + 4m]\\\\$

Step4; the resulting polynomial in standard form is,

$\rm (6m^5 + m^5) + [3 + (-6)] + [(-m^3) + (-2m^3)] + [(-4m) + 4m]\\\\ 7m^5-3m^2-3$

Hence, the subtraction in the standard form of the polynomial is $\rm 7m^5-3m^2-3$ .

To know more about Polynomial click the link given below.

brainly.com/question/26078031

3 0

2 years ago

Pls help me so I can pass

Naddika [18.5K]

Answer:

The slope of the line is constant. This is because all straight lines have a constant slope. The slope of this line is 1/3. When you use the legs to measure, the horizontal legs of the triangle, they increase in length by 3 units from the previous triangle. The vertical legs of the triangle also increase by 1 with each added triangle. Both of these observations support that the slope of the line is a constant 1/3.

Step-by-step explanation:

I know you were going to copy and paste so i put all above. Hope it helps you.

8 0

3 years ago

Read 2 more answers

A triangle is dilated with the center of dilation at point U. Point E is a vertex of the triangle and point E ′ E' is the corres

Snezhnost [94]

Answer: $scale\ factor=5$