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levacccp [35]
2 years ago
8

Calculate the length of ed and be

Mathematics
1 answer:
pashok25 [27]2 years ago
4 0

Answer:

ED = 6.5 cm

BE = 14.4 cm

Step-by-step explanation

AB/BC = AE/ED is less than or eqauls ED = BC×AE/AB

so

ED = 5×26/20 = 130/20 = 6.5 cm

and

AB/AC = BE/CD => BE = AB×CD/AC

so

BE = 20×18/25 = 360/25 = 14.4 cm

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Answer:

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Find: (6m5 3 â€"" m3 â€"" 4m) â€"" (â€""m5 2m3 â€"" 4m 6) Write subtraction of a polynomial expression as addition of the additi
aliina [53]

The subtraction in the standard form of the polynomial is \rm 7m^5-3m^2-3.

Given that

Expression; \rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6).

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According to the question

Expression; \rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6).

To find the subtraction of the polynomial follow all the steps given below.

  • Step1; Write the expression as an additive inverse.

                   \rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6)\\\\\rm (6m^5 + 3 - m^3 -4m) +(m^5 -2m^3 +4m - 6)

  • Step2; Rewrite terms that are subtracted as the addition of the opposite.

        \rm (6m^5 + 3 - m^3 -4m) +(m^5 -2m^3 +4m - 6)\\\\6m^5 + 3 + (-m^3) + (-4m) + m^5 + (2m^3) + 4m + (-6)

  • Step3; Group-like terms.

                   \rm 6m^5 + 3 + (-m^3) + (-4m) + m^5 + (2m^3) + 4m + (-6)\\\\(6m^5 + m^5) + [3 + (-6)] + [(-m^3) + (-2m^3)] + [(-4m) + 4m]\\\\

  • Step4; the resulting polynomial in standard form is,

                    \rm (6m^5 + m^5) + [3 + (-6)] + [(-m^3) + (-2m^3)] + [(-4m) + 4m]\\\\ 7m^5-3m^2-3

                   

Hence, the subtraction in the standard form of the polynomial is \rm 7m^5-3m^2-3.

To know more about Polynomial click the link given below.

brainly.com/question/26078031

                   

3 0
2 years ago
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Naddika [18.5K]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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A triangle is dilated with the center of dilation at point U. Point E is a vertex of the triangle and point E ′ E' is the corres
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Answer: scale\ factor=5

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