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3 years ago

CAN SOMEONE PLEASE HELP WITH THIS QUESTION ILL GIVE 20 FREE POINTS PLUS BRAINLIEST FOR CORRECT ANSWER !!!

Mathematics

2 answers:

Anton [14]3 years ago

6 0

Answer:

Step-by-step explanation:

The bar above the 3 in the 2.3 means that the 3 repeats indefinitely and the number is really 2.333333...which can also be 2 1/3 since 0.33333 = 1/3.

3 2/3 + 2 1/3

1/3 and 2/3 make 1

3 and 2 make 5

1 + 5 = 6

Adding together we get 6, so that is your answer.

I'm always happy to help :)

galben [10]3 years ago

4 0

Answer:

Step-by-step explanation:

The overbar means the digit repeats indefinitely. The repeating decimal 0.333... is equivalent to 1/3, so this is the simple addition ...

3 2/3 + 2 1/3 = 5 3/3 = 6

_____

<em>Comment on the repeating decimal</em>

1/3 = 0.3333... repeating is one of the first decimal equivalents you learn.

If you're into repeating decimals. you may have learned how to convert them to fractions:

x = 0.3333... repeating . . . . . . . give a name to the value

10x = 3.3333... repeating . . . . . multiply by 10^p where p is the number of digits in the repeating pattern

10x - x = 3.3333... - 0.3333... = 3 . . . . . subtract: the repeating portions cancel

9x = 3 . . . . . . . . . .simplify

x = 3/9 = 1/3 . . . . .divide by the x-coefficient; simplify

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PLEASE MAKE ME BRAINLIEST

7 0

3 years ago

The University of Washington claims that it graduates 85% of its basketball players. An NCAA investigation about the graduation

Nonamiya [84]

Probabilities are used to determine the chances of events

The given parameters are:

Sample size: n = 20
Proportion: p = 85%

<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 11) = ^{20}C_{11} \times (85\%)^{11} \times (1 - 85\%)^{20 -11}$

This gives

$P(x = 11) = 167960 \times (0.85)^{11} \times 0.15^{9}$

$P(x = 11) = 0.0011$

Express as percentage

$P(x = 11) = 0.11\%$

Hence, the probability that 11 out of the 20 would graduate is 0.11%

<h3>(b) To what extent do you think the university’s claim is true?</h3>

The probability 0.11% is less than 50%.

Hence, the extent that the university’s claim is true is very low

<h3>(c) What is the probability that all 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 20) = ^{20}C_{20} \times (85\%)^{20} \times (1 - 85\%)^{20 -20}$

This gives

$P(x = 20) = 1 \times (0.85)^{20} \times (0.15\%)^0$

$P(x = 20) = 0.0388$

Express as percentage

$P(x = 20) = 3.88\%$

Hence, the probability that all 20 would graduate is 3.88%

<h3>(d) The mean and the standard deviation</h3>

The mean is calculated as:

$\mu = np$

So, we have:

$\mu = 20 \times 85\%$

$\mu = 17$

The standard deviation is calculated as:

$\sigma = np(1 - p)$

So, we have:

$\sigma = 20 \times 85\% \times (1 - 85\%)$

$\sigma = 20 \times 0.85 \times 0.15$

$\sigma = 2.55$

Hence, the mean and the standard deviation are 17 and 2.55, respectively.