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2 years ago

CAN SOMEONE PLEASE HELP WITH THIS QUESTION ILL GIVE 20 FREE POINTS PLUS BRAINLIEST FOR CORRECT ANSWER !!!

Mathematics

2 answers:

Anton [14]2 years ago

6 0

Answer:

Step-by-step explanation:

The bar above the 3 in the 2.3 means that the 3 repeats indefinitely and the number is really 2.333333...which can also be 2 1/3 since 0.33333 = 1/3.

3 2/3 + 2 1/3

1/3 and 2/3 make 1

3 and 2 make 5

1 + 5 = 6

Adding together we get 6, so that is your answer.

I'm always happy to help :)

galben [10]2 years ago

4 0

Answer:

Step-by-step explanation:

The overbar means the digit repeats indefinitely. The repeating decimal 0.333... is equivalent to 1/3, so this is the simple addition ...

3 2/3 + 2 1/3 = 5 3/3 = 6

_____

<em>Comment on the repeating decimal</em>

1/3 = 0.3333... repeating is one of the first decimal equivalents you learn.

If you're into repeating decimals. you may have learned how to convert them to fractions:

x = 0.3333... repeating . . . . . . . give a name to the value

10x = 3.3333... repeating . . . . . multiply by 10^p where p is the number of digits in the repeating pattern

10x - x = 3.3333... - 0.3333... = 3 . . . . . subtract: the repeating portions cancel

9x = 3 . . . . . . . . . .simplify

x = 3/9 = 1/3 . . . . .divide by the x-coefficient; simplify

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12a^3b^2 +18a²b^2 – 12ab^2<br> Factor completely

AleksAgata [21]

The factorization of 12a^3b^2 +18a²b^2 – 12ab^2 is $6 a b^{2}(a+2)(2 a-1)$

<u>Solution:</u>

Given, expression is $12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

We have to factorize the given expression completely.

Now, take the expression

$12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

Taking $b^2$ as common term,

$b^{2}\left(12 a^{3}+18 a^{2}-12 a\right)$

Taking "a" as common term,

$b^{2}\left(a\left(12 a^{2}+18 a-12\right)\right)$

Taking "6" as common term,

$b^{2}\left(a\left(6\left(2 a^{2}+3 a-2\right)\right)\right)$

Splitting "3a" as "4a - a" we get,

$b^{2}\left(a\left(6\left(2 a^{2}+4 a-a-2\right)\right)\right)$

$\begin{array}{l}{b^{2}(a(6(2 a(a+2)-1(a+2))))} \\\\ {b^{2}(a(6((a+2) \times(2 a-1))))} \\\\ {6 a b^{2}(a+2)(2 a-1)}\end{array}$

Hence, the factored form of given expression is $6 a b^{2}(a+2)(2 a-1)$

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Anna35 [415]

Answer:

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Step-by-step explanation:

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