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2 years ago

What is the slope of the line represented by the equation y = 4/5x-3

Mathematics

1 answer:

defon2 years ago

7 0

<h2>Answer:</h2>

The slope of the given line is:

$\frac{4}{5}$

<h2>Step-by-step explanation:</h2>

We know that if a line is represented in the slope intercept form i.e.

$y=mx+c$

then m represents the slope of the line and c represents the y-intercept of the line.

Here we are given a equation of a line as follows:

$y=\frac{4}{5}x-3$

i.e. on comparing the equation with the slope-intercept form of the line we have the slope of the line is:

$m=\frac{4}{5}$

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Help me plss!! thank you!!

hichkok12 [17]

Answer:

24 feet

Step-by-step explanation:

160/100=1,6

1% - 1,6 square feet

100-5-25-45-10=15

1,6 x 15= 24

7 0

3 years ago

IN DESPERATE NEED OF HELP!!!! TIMED TEST!!! WILL GIVE BRAINLYEST!! No links or I will report u

ANEK [815]

Answer:

a) Slope is -4/3 y-intercept is 2

b) Slope is 2 y-intercept is -1

Step-by-step explanation:

y=mx+c

m=gradient (or in this case slope)

c=y-intercept

6 0

3 years ago

Solve the simultaneous equation<br> 2x+4y=1<br> 3x+5y=7b

Lyrx [107]

Step-by-step explanation:

3x+5y=7b equation 1
2x+4y=1

2x=-4y+1

x=(-4y+1)/2
x=(-4y+1)/2 in equation 1

3×(-4y+1)/2+5y=7b

(-12y+3)/2+5y=7b

(-12y+3+10y)/2=7b

(-12y+3)/2=7b

-12y+3=14b

-12y=14b-3

y=3-14b/12
y=3-14b/12 in x=(-4y+1)/2

x=(-4×{3-14b/12}+1)/2

x=(-3+14b)/3+1/2

x=14b/3×1/2

x=7b/3

8 0

3 years ago

Asher opened a savings account by making an initial deposit and setting up weekly automatic deposits as shown in the graph. How

Sergio [31]

Answer:

y = 7.5x + 20

Step-by-step explanation:

As per the graph, the y-intercept is 20 which is the initial amount.

Another marked point has coordinates (4, 50).

<u>The slope is:</u>

m = (50 - 20)/4 = 7.5

<u>The equation of the line is:</u>

y = 7.5x + 20

$20 is the initial deposit and weekly deposit is $7.5

5 0

3 years ago

Read 2 more answers

Neeeeed helpppppp please

MissTica

Answer:

Scale factor = 7

Step-by-step explanation:

Dilation with scale factor to map HEFG to DABC will be,

Scale factor = $\frac{\text{Dimension of Image DABC}}{\text{Dimension of preimage HEFG}}$

= $\frac{\text{Length of CD}}{\text{Length of GH}}$

Length of CD = Distance between two points C(0, -7) and D(-7, 0)

= $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

= $\sqrt{(-7-0)^2+(0+7)^2}$

= $\sqrt{98}$

= $7\sqrt{2}$

Length of GH = Distance between G(0, -1) and H(-1, 0)

= $\sqrt{(-1-0)^2+(0+1)^2}$

= $\sqrt{2}$

Scale factor = $\frac{7\sqrt{2} }{\sqrt{2} }$

= 7

6 0

3 years ago