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Gnom [1K]
3 years ago
12

The slope of a horizontal line is ___?

Mathematics
2 answers:
mote1985 [20]3 years ago
8 0
0. The answer is Z E R O . Go ahead, google it. Google what you just wrote. No really, do it before I _____
svet-max [94.6K]3 years ago
8 0
The slope is 0 because the slope measures how steep the line is and a flat line is not steep at all
You might be interested in
ASAP NEEEEED HELLLLLLLLLP PLZZZ
nadya68 [22]
T = 5 a
i = 4% aa
j = 1200
c = ...
j = cit/100
c = 100j / it
c = 100*1200 / 4*5
c = 120000 / 20
c = 12000/2
c = 6000

montante

M = c+j
M = 6000+1200
M = 7200
7 0
3 years ago
Match the parabolas represented by the equations with their vertices. y = x2 + 6x + 8 y = 2x2 + 16x + 28 y = -x2 + 5x + 14 y = -
GaryK [48]

Consider all parabolas:

1.

y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

2.

y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

3.

y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

4.

y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

5.

y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

6.

y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.

When x=2, y=13, then the point (2,13) is vertex of this sixth parabola.

3 0
3 years ago
2•log(x – 3) = log 25
AfilCa [17]

Answer:

Step-by-step explanation:

2log(x-3)=log25

log(x-3)²=log25 cancel out log on both sides

(x-3)²=25

x²-6x+9=25

x²-6x+9-25=0

x²-6x-16=0 factorize

x²+2x-8x-16=0

x(x+2)-8(x+2)

(x-8)(x+2)=0

x-8=0 or x+2=0

x=8 or x=-2

x=-2 cannot be considered because of the -ve sign.

x=8.

check

2log(x-3)

2log(8-3)

2log5

log5²=25

therefore LHS=RHS

8 0
3 years ago
Evaluate. <br> 6[5(3-9)-1]+2/7(8-2)+4
GREYUIT [131]
If you would like to evaluate 6 * [5 * (3 - 9) - 1] + 2 / 7 * (8 - 2) + 4, you can calculate this using the following steps:

6 * [5 * (3 - 9) - 1] + 2 / 7 * (8 - 2) + 4 = 6 * [5 * (-6) - 1] + 2/7 * 6 +  4 = 6 * [- 30 - 1] + 12/7 + 4 = 6 * [- 31] + 12/7 + 4 = - 186 + 12/7 + 4 = - 182 + 12/7 = - 1274/7 + 12/7 = - 1262/7

The correct result would be - 1262/7.
6 0
4 years ago
Read 2 more answers
Which factorization is equivalent to this expression<br> -32xy + 20y - 14
densk [106]

Answer:

-2(16xy-10y+7)

Step-by-step explanation:

-2(16xy-10y-7)= -2×16xy-2(-10y)-2×7

-2(16xy-10y+7)= -32xy+20y-14

3 0
3 years ago
Read 2 more answers
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