Answer:
False
Step-by-step explanation:
given that a race car driver tested his car for time from 0 to 60 mph, and in 20 tests obtained an average of 4.85 seconds with a standard deviation of 1.47 seconds.
Sample size n = 20
since population standard deviation is not known, we can use t critical value for finding out the confidence interval
df=19
t critical = 2.045
Margin of error = 
conidence interval = Mean±Margin of error
= 
The given confidence interval is (4.52, 5.18)
Hence the statement is false.
1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
The range of a function is the set of y-coordinates of all the points int he graph of the function.
Look at the graph. The vertex is point (2, -3).
The graph does not go lower than that point.
The lowest y-coordinate is -3.
The graph goes up forever on both sides until infinity.
The range is all numbers greater than or equal to -3.
Xy = 6
x + y = 9
x + y = 9
x - x + y = -x + 9
y = -x + 9
xy = 6
x(-x + 9) = 6
x(-x) + x(9) = 6
-x² + 9x = 6
-x² + 9x - 6 = 0
-1(x²) - 1(-9x) - 1(6) = 0
-1(x² - 9x + 6) = 0
-1 -1
x² - 9x + 6 = 0
x = -(-9) ± √((-9)² - 4(1)(6))
2(1)
x = 9 ± √(81 - 24)
2
x = 9 ± √(57)
2
x = 4.5 ± 0.5√(57)
x + y = 9
4.5 ± 0.5√(57) + y = 9
- (4.5 ± 0.5√(57)) - (4.5 ± 0.5√(57))
y = 4.5 ± 0.5√(57)
(x, y) = (4.5 ± 0.5√(57), 4.5 ± 0.5√(57))
The two numbers that multiply to 6 and add up to 9 are 4.5 ± 0.5√(57).
Answer:
1.1, -5
Step-by-step explanation:
53 - 9y = 1
from equation i
53-9y = 1
-9y= 1-53 = -52
y = -52/-9= 52/9 = 5⁷/₉
-7.2 + 2y = -5
add 7.2 to both sides
2y= -5+7.2 = 2.2
y= 2.2/2 = 1.1
