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jasenka [17]
2 years ago
14

Football boot sizes of a football team continuous or discrete

Mathematics
1 answer:
algol [13]2 years ago
6 0

Answer:

discrete?

according to probability of basic things we know that there are more people different than same so there is more than enough probability of those sizes being discrete.

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Simplify<br> 4-3[6-2(4-3)]
ikadub [295]

Answer:

<h2>-8</h2>

Step-by-step explanation:

4-3[6-2(4-3)]\\\\Follow\:the\:PEMDAS\:order\:of\:operations\\\\\mathrm{Calculate\:within\:parentheses}\:\left[6-2\left(4-3\right)\right] : 4\\\\=4-3\times\:4\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:3\times\:4\::\quad 12\\=4-12\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:4-12\:\\\\:\quad -8

4 0
3 years ago
Pretend we all live in the same house in the comments <br> Funniest gets brainliest.
natulia [17]

Answer:

fune

Step-by-step explanation:

pls laugh or mom will lock me in basement again

6 0
3 years ago
How is this supposed to be solved, i don’t really understand.
dezoksy [38]

Answer:

$2561.99 a quarter

Step-by-step explanation:

Just add together what they pay every year, then multiply by 25.5% (because that's the quarterly premium.)

Annual cost = insurance + dental + vision

                    = 8900 + 772 + 375 = $10047 a year.

Quarterly cost = 25.5% of annual cost

   Whenever you see of, think of multiplication!

   25.5% = .255

Quarterly cost = .255 * 10047 = <u>$2561.99 a quarter</u>

5 0
3 years ago
Find the intersection points using substitution or elimination for each system of equations:
natka813 [3]

Answer:

Step-by-step explanation:

Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.

Problem 1:

(x²)/4 +y²= 1

y= x+1

*substitute for y*

Now we have a one-variable equation we can solve-

x²/4 + (x+1)² = 1

x²/4 + (x+1)(x+1)= 1

x²/4 + x²+2x+1= 1

*subtract 1 from both sides to set equal to 0*

x²/4 +x^2+2x=0

x²/4 can also be 1/4 * x²

1/4 * x² +1*x² +2x = 0

*combine like terms*

5/4 * x^2+2x+ 0 =0

now, you can use the quadratic equation to solve for x

a= 5/4

b= 2

c=0

the syntax on this will be rough, but I'll do my best...

x= (-b ± √(b²-4ac))/(2a)

x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))

x= (-2 ±√(4-0))/(2.5)

x= (-2±2)/2.5

x will have 2 answers because of ±

x= 0 or x= 1.6

now plug that back into one of the equations and solve.

y= 0+1 = 1

y= 1.6+1= 2.6

Hopefully this explanation was enough to help you solve problem 2.

Problem 2:

x² + y² -16y +39= 0

y²- x² -9= 0

6 0
3 years ago
Help, please I would appreciate it.
Veronika [31]
At firt we should solve what is h(0)
h(0)=0^2+2
h(0)=2
So then you should take the h(0) answer to g(x) and the result is g(2)= -2-5=-7
3 0
3 years ago
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