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jasenka [17]
2 years ago
14

Football boot sizes of a football team continuous or discrete

Mathematics
1 answer:
algol [13]2 years ago
6 0

Answer:

discrete?

according to probability of basic things we know that there are more people different than same so there is more than enough probability of those sizes being discrete.

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Radius of a circle with a circumference of 28 (3.14)
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Answer:the answer is 82.9


Step-by-step explanation:

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Help asap 25 points worth pre alg<br> x=<br> y=
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Firstly Substitute y=2x-5 into 5x-4y=-10

This will be 5x-4(2x-5)=10 now solve for x

5x-8x+20=-10

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Now sub x as 10 into the second equation y=2x-5

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A right triangle has a hypotenuse of 43 cm and an angle of 56° opposite leg m. What is the length of leg m rounded to the neares
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The number of motor vehicles registered in millions in the US has grown as follows:
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Answer:

a) Figure attached

b) r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=10 \sum x = 75.819, \sum y = 43.5231, \sum xy = 330.0321, \sum x^2 =574.8598, \sum y^2 =192.8274  

r=\frac{10(330.0321)-(75.81948)(43.5231)}{\sqrt{[10(574.8598) -(75.819)^2][10(192.8274) -(43.5231)^2]}}=0.989  

So then the correlation coefficient would be r =0.989

Step-by-step explanation:

Previous concepts

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

Solution to the problem

Part a

Year (x): 1940, 1945 1950, 1955, 1960, 1965, 1970, 1975, 1980, 1985

Vehicles (Y): 32.4, 31.0, 49.2, 62.7, 73.9, 90.4, 108.4, 132.9, 155.8, 171.7

After apply natural log for the two variables and create the scatterplot in excel we got the following result on the figure attached.

Part b

And in order to calculate the correlation coefficient we can use this formula:  

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=10 \sum x = 75.819, \sum y = 43.5231, \sum xy = 330.0321, \sum x^2 =574.8598, \sum y^2 =192.8274  

r=\frac{10(330.0321)-(75.81948)(43.5231)}{\sqrt{[10(574.8598) -(75.81948)^2][10(192.8274) -(43.5231)^2]}}=0.989  

So then the correlation coefficient would be r =0.989

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