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2 years ago

Write an algebraic expression for each word expression.

Mathematics

1 answer:

coldgirl [10]2 years ago

7 0

Answer:

27) 14x

28) n/9

29) A number, z, divided by 11

30) The sum of a number, z, and 11

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Michaela is training for a race. She runs 5 miles in 52 minutes. Her goal is to run 6 miles in 1 hour. By how many minutes per m

Leya [2.2K]

Answer:

2 min

Step-by-step explanation:

she runs 5 miles in 52 min

her goal is 6 miles

so if 5 miles is completed in 50 min then 1 mile = 10 min

and 6 mile = 60 min

6 0

2 years ago

PLSSS HELLPPPPP ASAPPP

padilas [110]

I believe it would be 80

8 0

2 years ago

Read 2 more answers

In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
$a\cdot r$ ,
$a \cdot r^2$ ,
$a \cdot r^3$ ,
$a \cdot r^4$ .

First equation:

$a\, r^4 - a = 150$ .

Second equation:

$a\, r^3 - a\, r = 48$ .

Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

$a\, r\, \left(r^2 - 1\right) = 48$ .

Take the quotient between these two equations:

$\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}$ .

Simplify and solve for $r$ :

$\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}$ .

$8\, r^2 - 25\, r + 8 = 0$ .

Either $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ or $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ .

Assume that $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

Similarly, assume that $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}$ .

4 0

2 years ago

Please help, i’ll mark brainliest.

nalin [4]

Answer:

264 cu

Step-by-step explanation:

This is because you have to add it from all sides, the first prism is 144 cu and then the second one is, 120, and when you add both of those together you get 264

<u><em>Thus the answer is....264</em></u>

5 0

2 years ago

Pls answer 26 and show work

Phoenix [80]

The transformed equation y = -(x - 2)^2 - 3 compared to the parent function involves translating the parent function to the right by 2 units, reflecting the function across the y-axis and translating the function 3 units down

<h3>How to compare the function to its parent function?</h3>

The equation of the transformed function is given as:

y = -(x - 2)^2 - 3

While the equation of the parent function is given as

y = x^2

Start by translating the parent function to the right by 2 units.

This is represented as:

(x, y) = (x - 2, y)

So, we have:

y = (x - 2)^2

Next, reflect the above function across the y-axis

This is represented as:

(x, y) = (-x, y)

So, we have:

y = -(x - 2)^2

Lastly, translate the above function 3 units down

This is represented as:

(x, y) = (x, y - 3)

So, we have:

y = -(x - 2)^2 - 3

Hence, the transformed equation y = -(x - 2)^2 - 3 compared to the parent function involves translating the parent function to the right by 2 units, reflecting the function across the y-axis and translating the function 3 units down

Read more about function transformation at:

brainly.com/question/8241886

#SPJ1

7 0

1 year ago