D is the answer to the question
Answer:
Cost of adult ticket = $12.5
Cost of child ticket = $7.5
Step-by-step explanation:
Given:
Cost of 6 adult ticket and 5 child ticket = $112.5
Cost of 8 adult ticket and 4 child ticket = $130
Find:
Equation and solution
Computation:
Assume;
Cost of adult ticket = a
Cost of child ticket = b
So,
6a + 5b = 112.5....eq1
8a + 4b = 130 ......eq2
Eq2 x 1.25
10a + 5b = 162.5 .....eq3
eq3 - eq1
4a = 50
Cost of adult ticket = $12.5
8a + 4b = 130
8(12.5) + 4b = 130
Cost of child ticket = $7.5
2x + 5y = -3 ⇒ 2x + 5y = -3
1x + 8y = 4 ⇒ <u>2x + 16y = 8
</u> -<u>11y</u> = <u>-11 </u>
-11 -11
y = 1
2x + 5(1) = -3
2x + 5 = -3
<u> -5 -5</u>
<u>2x</u> = <u>-8</u>
2 2
x = -4
(x, y) = (-4, 1)
2x + 1y = 7 ⇒ 2x + 1y = 7
1x - 2y = -14 ⇒ <u>2x - 4y = -28</u>
<u>5y</u> = <u>35</u>
5 5
y = 7
2x + 7 = 7
<u> -7 -7</u>
<u>2x</u> = <u>0</u>
2 2
x = 0
(x, y) = (0, 7)
Answer:
Neither linear nor exponential
Step-by-step explanation:
To check for a linear relationship. Find slope.
slope= (-1 - (-2)) / ( 5 - 2) = 1/3
check other points
slope = (1 - (-1) )/ (8 - 5) = 2/3
check more
slope = (4 - 1) / (11 - 8) = 3/ 3 = 1
Nope.
try assuming an exponential:
y = c * (a^x)
-2 = c* (a^2); -2/c = a^2
-1 = c *(a ^5); -1/c = a^5
1 = c * (a^8), 1/c = a^8
(-2/c)^4 = a^8 = 1/c
16/(c^4) = 1/c
c^3 = 16, then a = root (-2/ cube-root(16) )
The change from negative to postive would not work for y = c(a^x)
so...
assume y = a^x + k
-2 = a^2 + k
-1 = a^5 + k
... I would say neither..
Answer:
3 students are eating lunches other than salads and sandwiches.
Step-by-step explanation:
To solve this you know that there are 18 students in the cafeteria and 1/6 of them are eating salads and 2/3 are eating sandwiches right? So you would have to think about what 1/6 of 18 is so you know how many students are eating salads, and 1/6 of 18 is 3 so there are 3 students eating salads. Now, you have to find out how many students are eating sandwiches, so you need to know what 2/3 of 18 is. 2/3 of 18 is 12 so now you also know that there are 12 students eating sandwiches. Next, you have to add 12 and 3 and you get 15. Since you know that there are 18 students in the cafeteria, you have to subtract 18 by 15, and you should get 3. So 3 students are eating lunches other than salads or sandwiches.
Hope this helps you! :D
