Okay what’s the rest of the question ?
radius = 7
the equation of a circle in standard form is
(x-a)² + (y-b)² = r²
where (a, b) are the coordinates of the centre and r is the radius
To obtain this form ' complete the square ' on both the x and y terms
x² + 2(1)x + 1 + y² + 2(3)y + 9 = 39 + 1 + 9
(x+1)² + (y+3)² = 49 ← in standard form
with centre (1, 3) and r = √49 = 7
Answer:
(x-4) (x-3) (x+3)
Step-by-step explanation:
x^3 - 4x^2 - 9x + 36
Make 2 groups
x^3 - 4x^2 - 9x + 36
We can factor out x^2 from the first group and -9 from the second group
x^2 (x-4) - 9(x-4)
Now factor out (x-4)
(x-4) (x^2 -9)
This may be an answer choice but we can still factor
(x^2 -9) is the difference of squares
(x^2-9) = (x-3) (x+3)
Replacing this
(x-4) (x-3) (x+3)
Answer:
w=4.9
Step-by-step explanation:
If you are solving for w, you want to isolate the variable. If it is easier to write it out, it would look something like this..
-5 x w = -24.5
To get w by itself, use the inverse of multiplication, which is division. Divide the expression to the left of the equal sign by -5. Remember, what you do to one side, you must do to the other. When you divide -24.5 by -5, you end up with
w=4.9
The Centers are, <span>Center (3, -2), radius = 5 </span>
<span>Center (0, 0), radius = 4 </span>
<span>Center (5, 2), radius = 3</span>
