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mel-nik [20]
3 years ago
14

The sum of 4 and y divided by 5 equal to 9. Find the value of y.​pls a better solution

Mathematics
1 answer:
rosijanka [135]3 years ago
6 0

Answer:

y=41

Step-by-step explanation:

Let us start by writing an equation. <em>4 plus y divided by 5 equals to 9</em> :

\frac{4+y}{5}=9

Great! Now let us solve for the variable, <em>y</em>, by isolating the terms:

4+y=45\\y=41

<em>I hope this helps! Let me know if you have any questions :)</em>

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Step-by-step explanation:

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3 years ago
Terrence opens a savings account with a deposit of $1000. After 1 year he receives $50 in interest. What is the annual interest
geniusboy [140]

Answer:

Step-by-step explanation:

So, I'm pretty sure this is a problem about compound interest.

The formula for compound interest is A = p(1 + r/n)^nt

For this problem, $1000 is p, the initial amount; A is the total amount, or $1050.

What the problem is asking for is r, the interest rate, which is divided by n. N is the number of times the interest rate is compounded per year; Since the question is asking for the annual interest rate, N would be equal to 1. And because Terrence is has only left his money in for a year, t would also be equal to one.

So, by filling in the formula some, we get this:

$1050 = $1000(1 + r/1)^1*1

To find r, we would need to isolate it in the problem.

1. First, distribute $1000 to the parenthesis(keep in mind that 1000, is also equal to 1000/1:

1050 = (1000 + 1000r/1)^1

2. Then subtract 1000 from both sides:

50 = (1000r/1)^1

3. Multiple both sides by one:

50 = (1000r)^1

4. Divide both sides by 1000:

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8 0
3 years ago
Solve (2x + 5)= (2x + 3)(2x - 1)
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(2x + 5)= (2x + 3)(2x - 1)\\2x+5=4x^2-2x+6x-3\\4x^2-2x+6x-3-2x-5=0\\4x^2+2x-8=0\\(4x+1-\sqrt{33})( 4x+1+\sqrt{33})=0 \\ x=\frac{-1+\sqrt{33} }{4} /or/x=\frac{-1-\sqrt{33} }{4}

4 0
2 years ago
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Can someone help me and explain? I will mark brainlest. ♡
Sedbober [7]

Answer:

p'(4) = -3

q'(8) = \frac{1}{4}\\

Step-by-step explanation:

For p'(4):

p(x) = f(x)g(x) \\ p'(x) = \frac{d}{dx}(f(x)g(x)) \\ p'(x) = f'(x)g(x) +f(x)g'(x)

p'(4) = f'(4)g(4) + f(4)g'(4) \\ p'(4) = (-1)(3) +(7)(0) \\ p'(4) = -3

For q'(8):

q(x) = \frac{f(x)}{g(x)} \\ q'(x)= \frac{d}{dx}(\frac{f(x)}{g(x)}) \\ q'(x) = \frac{f'(x)g(x) -f(x)g'(x)}{{g(x)}^2}

q'(8) = \frac{f'(8)g(8) -f(8)g'(8)}{{g(8)}^2} \\ q'(8) = \frac{(2)(2) -(6)(\frac{1}{2})}{{2}^2} \\ q'(8) = \frac{4 -3}{4} \\ q'(8) = \frac{1}{4}

4 0
3 years ago
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