Check the picture below, so let's check the equations below hmmm
![\boxed{A}\\\\ y=\cfrac{16-3x}{4}\implies y=\cfrac{-3x+16}{4}\implies y = \cfrac{-3x}{4}+\cfrac{16}{4}\implies y=-\cfrac{3}{4}x\stackrel{\stackrel{b}{\downarrow }}{+4}~\hfill \bigotimes \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cboxed%7BA%7D%5C%5C%5C%5C%20y%3D%5Ccfrac%7B16-3x%7D%7B4%7D%5Cimplies%20y%3D%5Ccfrac%7B-3x%2B16%7D%7B4%7D%5Cimplies%20y%20%3D%20%5Ccfrac%7B-3x%7D%7B4%7D%2B%5Ccfrac%7B16%7D%7B4%7D%5Cimplies%20y%3D-%5Ccfrac%7B3%7D%7B4%7Dx%5Cstackrel%7B%5Cstackrel%7Bb%7D%7B%5Cdownarrow%20%7D%7D%7B%2B4%7D~%5Chfill%20%5Cbigotimes%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
90 cm because ................................
Answer:
7.3
Step-by-step explanation:
The mean of 4.6, 3, 8.1, 9, 12, 3, 9, 3.5, 7, 3.
6, 22
, 5.8
, 9
, 3 is 7.3
To solve this problem, let us first assign variables. Let
us say that:
A = runner
B = cyclist
d = distance
v = velocity
time = t
The time in which the cyclist overtakes the runner is the
time wherein the distance of the two is the same, that is:
dA = dB
We know that the formula for calculating distance is:
d = v t
therefore,
vA tA = vB tB
Further, we know that tA = tB + 2, therefore:
vA (tB + 2) = vB tB
4 (tB + 2) = 14 tB
4 tB + 8 = 14 tB
10 tB = 8
tB = 0.8 hours = 48 min
Therefore the cyclist overtakes the runner after 0.8
hours or 48 minutes.
