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UkoKoshka [18]
3 years ago
7

A person who weighs 160 pounds on Earth will weigh approximately 380 pounds on Jupiter. Sam makes this table to help him determi

ne how much a person who weighs 120 pounds on Earth will weigh on Jupiter:
Which equation shows what Sam can do next to determine how much a person who weighs 120 pounds on Earth will weigh on Jupiter, yy?

Mathematics
2 answers:
zhannawk [14.2K]3 years ago
8 0
220
The answer is 220 as the y= 220
vladimir2022 [97]3 years ago
7 0

Answer:

220

Step-by-step explanation:

the answers is 220 as the y=220

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Consider a political discussion group consisting of 4 ​Democrats, 4 ​Republicans, and 5 Independents. Suppose that two group mem
kumpel [21]

steps:
total: 13 ppl
republicans: 4
1st person: 13-4/13 9/13
2nd person: 12-4/12 (because one person was taken out). 8/12
6 0
3 years ago
Find the product of 9 and 583. <br><br> A. 64 <br> B. 592 <br> C. 5,247 <br> D. 5,347
Dmitry_Shevchenko [17]

Answer:

C. 5,247

Step-by-step explanation:

  1. Product = multiplication
  2. The product of 9 and 583: 9 × 583 = 5,247

I hope this helps!

7 0
3 years ago
Read 2 more answers
Calculate the average rate of change of f(x) = 1 x - x2 - 2 for 3 ≤ x ≤ 6. A) -163 18 B) -18 163 C) 163 18 D) 18 163
larisa86 [58]
To solve this we are going to use the average rate of change formula: A(x)= \frac{f(b)-f(a)}{b-a}
where
A(x) is the average rate of change of the function
f(a) is the position function evaluated at a
f(b) is the position function evaluated at b
a is the first point in the interval
b is the second point in the interval

We can infer for our problem that the first point is 3 and the second point is 6, so a=3 and b=6. Lets replace those values in our formula:
A(x)= \frac{f(b)-f(a)}{b-a}
A(x)= \frac{f(6)-f(3)}{6-3}
A(x)= \frac{6-6^2-2-(3-3^2-2)}{3}
A(x)= \frac{-32-(-8)}{3}
A(x)= \frac{-32+8}{3}
A(x)= \frac{-24}{3}
A(x)=-8

We can conclude that the average rate of change of the function f(x) = 1 x - x2 - 2 for <span>3 ≤ x ≤ 6 is -8</span>
3 0
3 years ago
Read 2 more answers
A bar graph titled Album Type Sold per Year has year on the x-axis and number of albums sold on the y-axis. For C D s, in 2008 t
stira [4]

Answer:

True, True, False, True, False, True

Step-by-step explanation:

<u>CDs have a higher mean than digital</u>

<u />

Let's check.  CD mean is (1000 + 800 + 800 + 600 + 400 + 200)/6 = 633.33

Digital mean: (100 + 300 + 300 + 500 + 700 + 900)/6 = 466.67

CD's mean is higher.  Since you are dividing byt he same number you also could have just added the amount and found which was a larger number.  But yes, this is true.

<u>The range of digital is 800</u>

<u />

The range is the highest number inus the lowest number.  For digital the highest is 900 and lowest is 100 so the ange is 900-100 = 800.  So this is true.

<u>The median of CDs is 400. </u>

<u />

The median is the middle value for odd numbers of values, or the average of the two middle values.  6 total values means you have to take the third and fourth and average them.  in CDs the middle values are 800 and 600, the average is 700, so that is what the median is.  this is false.

<u>Both have the same interquartile range. </u>

<u />

Interquartile range is to find the middle number or numbers like in median, then take the two parts it is split into and find the "median" of those.  Then subtract the larger one fromt he smaller one.

IQR of CD the first half is 200, 400, 600 so the middle here is 400, second half has a middle number of 800 so IQR here is 800-400=400

IQR of digital is 700-300 = 400 so yes both are the same.

<u>Both have the same median</u>

<u />

We know the medan of CDs is 700 then findign the median of digital is (300+500)/2 = 400.  So no, the medians are not the same.

<u>Digital’s mean is around 467. </u>

<u />

We founf the mean for digital to be 466.67 which rounds up to 467, So I would say it is true.

8 0
4 years ago
Read 2 more answers
Ellen claims she has a coin that is weighted so that the probability of heads is 70%.
kvasek [131]
<span>Outcome Heads Tails
Relative Frequency 0.69 0.31

so first statement is false as 69% is close to 70%.

second statement is false as heads probability is close to 70%

last 2 statements are true:

</span><span>The theoretical probability of tails is most likely 30%.

It is likely that the coin is not fair.
</span>
5 0
3 years ago
Read 2 more answers
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