If M is the midpoint of XY and XM=2x+5 and MY=3x-1, then what is the length of MY?

I need help NOW!!!!!! Thanks!

Mekhanik [1.2K]

Answer: Good thing you provided the image!

Working down the columns:

C base= 2

D base = 4

C height =3

D height = 2

C area = bh = 8

D area = bh = 8

Step-by-step explanation:

Try thinking about drawing a rectangle around the entire image of C and D, connecting each of the corners (sort of like what is being done for B) and then you can perceive the b and h.

The trick to D is to turn your head 90 degrees (or sideways) so you can see those 4 boxes as the base.

For C the base is the 2 boxes, and going up until you meet the other parallel side you can count 4 boxes.

I usually default to using the side which I can easily count boxes as the base and go from there.

4 0

3 years ago

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Can someone help me with this? The teacher assigned this for homework even though we haven't learned about this yet...... it's a

Solnce55 [7]

Answer:

f is a function because each student, or each element of the domain, corresponds to one element of range.

Step-by-step explanation:

function is each input has one output. input is domain, output is range

8 0

3 years ago

Which is an example of a financial change that we require budgetary consideration

Anvisha [2.4K]

Answer:

oh i dont know :0

Step-by-step explanation:

8 0

3 years ago

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A manufacturer of sprinkler systems designed for fire protection claims that the average activating temperature is at least 135°

nirvana33 [79]

Answer:

$z=\frac{133-135}{\frac{3.3}{\sqrt{32}}}=-3.428$

$p_v =P(z$

If we compare the p value and the significance level given for example $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean is significantly lower than 135 so the claim not makes sense

Step-by-step explanation:

Data given and notation

$\bar X=133$ represent the sample mean

$\sigma=3.3$ represent the standard deviation for the population

$n=32$ sample size

$\mu_o =135$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mena is at least 135, the system of hypothesis would be:

Null hypothesis: $\mu \geq 135$

Alternative hypothesis: $\mu < 135$

We know the population deviation, so for this case is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{133-135}{\frac{3.3}{\sqrt{32}}}=-3.428$

Calculate the P-value

Since is a one-side lower test the p value would be:

$p_v =P(z$

Conclusion

If we compare the p value and the significance level given for example $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean is significantly lower than 135 so the claim not makes sense

3 0

3 years ago

Volume=<br> Help me please thanks so much

Artemon [7]

Answer:

30.7

Step-by-step explanation:

It's 30.7 because 707/23

4 0

2 years ago

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