All categories

3 years ago

Given f(x) and g(x) = f(x) + k, look at the graph below and determine the value of k.

Mathematics

2 answers:

blagie [28]3 years ago

4 0

Answer:

k=4

Step-by-step explanation:

I took the test

Anton [14]3 years ago

3 0

Answer:

Given the graph $f(x) = \frac{1}{3}x -2$ and $g(x) = \frac{1}{3}x + 3$

We have to find the value of k;

Since, g(x) = f(x) +k

$\frac{1}{3}x+3 = \frac{1}{3}x-2 +k$

Subtract $\frac{1}{3}x$ from both sides we get;

$3 = -2 +k$

Add 2 to both sides we get;

$3+2 = -2 +k +2$

Simplify:

$5 = k$

k = 5

Therefore, the value of k = 5

You might be interested in

What is the smallest number by which 9408 must be divided so that the quotient is perfect cube?

Mandarinka [93]

Answer:

Out of the prime factors of 9408, only 3 is without pair. So, 3 is the number by which 9408 must be divided to make the quotient a perfect square.

7 0

3 years ago

Read 2 more answers

Simplify (4xy^-2)/(12x^(-1/3)y^-5) and Show work ...?

oee [108]

The answer is $\frac{x^{4/3}y^{3}}{3}$ .

The fraction is: $\frac{4xy^{-2} }{12 x^{-1/3} y^{-5} }$
Let's rewrite it: $\frac{4xy^{-2} }{12 x^{-1/3} y^{-5} }=\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }$

Since $\frac{x^{a} }{x^{b}} =x^{a-b}$ ,
then:
*** $\frac{x}{ x^{-1/3} }= x^{1-(-1/3)} = x^{3/3+1/3} = x^{4/3}$
*** $\frac{y^{-2} }{ y^{-5} }= y^{-2-(-5)} = y^{-2+5} = y^{3}$
______
$\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }= \frac{1*4}{3*4}* x^{4/3}*y^{3}= \frac{1}{3} * x^{4/3}*y^{3}= \frac{x^{4/3}y^{3}}{3}$

8 0

3 years ago

Investing in bonds! PLS HELP

ozzi

1) A zero coupon bond is a bad choice for Ralph because it is a bond bought at a very deep discount but does not earn any interest. He will only get the face value of the bond when it matures.

2) Defaulting means being unable to pay for the debt in time. They will pay for the debt when they have the available funds to do so. Allison will just have to wait until the Greek government has enough money to cover their debts.

3 0

3 years ago

Solve for x. Assume that lines which appear tangent are tangent.

REY [17]

Remark
Secants going through a circle form a ratio that's the same for all secants going through the circle and beginning at 1 point. See the diagram below for the ratio. Follow the Line designations carefully. This comes up many times.

General Ratio is (segment from the external point to the the first intersect point of the circumference divided by the distance from the external point to the second intercept point on the circumference).

General Ratio
Put in terms of the diagram the general ratio is (OA / OB)

Equation
OA/OB = OC/OD

Substitute and Solve
9/(9 + 11) = 10/(10 + x)
9/20 = 10/(10 + x) Notice that you can't combine the right side. Cross Multiply

9*(10 + x) = 10 * 20 Remove the brackets on the left. Combine the right factors.
90 + 9x = 200 Subtract 90 from both sides.
9x = 200 - 90
9x = 110 Divide by 9
110 / 9 = 12.22

4 0

3 years ago

Suppose f is a function. If 10 = f(-4), find the coordinates of a point on the graph of f?

Rashid [163]

Given:

For a function f, $10 = f(-4)$ .

To find:

The coordinates of a point on the graph of f.

Solution:

We have,

$10 = f(-4)$

It means the value of function f is 10 at -4.

On a coordinate plane x-axis represents the input values and y-axis represents the output values of a function. So,

x-coordinate = input value = -4

y-coordinate = output value = 10

Therefore, the required coordinates of a point on the graph of f are (-4,10).

5 0

4 years ago