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EastWind [94]
3 years ago
14

Given f(x) and g(x) = f(x) + k, look at the graph below and determine the value of k.

Mathematics
2 answers:
blagie [28]3 years ago
4 0

Answer:

k=4

Step-by-step explanation:

I took the test

Anton [14]3 years ago
3 0

Answer:

Given the graph f(x) = \frac{1}{3}x -2 and g(x) = \frac{1}{3}x + 3

We have to find the value of k;

Since, g(x) = f(x) +k

\frac{1}{3}x+3 = \frac{1}{3}x-2 +k

Subtract \frac{1}{3}x from both sides we get;

3 = -2 +k

Add 2 to both sides we get;

3+2 = -2 +k +2

Simplify:

5 = k

or

k = 5

Therefore, the value of k = 5


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Write the quadratic function in vertex form, then identify the vertex
34kurt

Answer:

vertex = (- 10, - 10 )

Step-by-step explanation:

The equation of a quadratic in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

To obtain this form use the method of completing the square.

Given

h(x) = x² + 20x + 90

add/subtract ( half the coefficient of the x- term )²

h(x) = x² + 2(10)x + 100 - 100 + 90

      = (x + 10)² - 10 ← in vertex form

with (h, k ) = (- 10, - 10 )

8 0
3 years ago
Manuel has pennies and nickels with a total value of $1.15. The number of nickels is 43 less than the number of pennies. How man
Veseljchak [2.6K]

Answer:

45 Pennies

14 Nickels

Step-by-step explanation:

1.15 - .43 = .72

72 % 5 = 14.? - 14 nickels

.2 left - 2 pennies

7 0
3 years ago
Ninety-one percent of products come off the line within product specifications. Your quality control department selects 15 produ
Allisa [31]

Answer:

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

Step-by-step explanation:

There is a random binomial variable X that represents the number of units come off the line within product specifications in a review of n Bernoulli-type trials with probability of success 0.91. Therefore, the model is {15 \choose x} (0.91) ^ {x} (0.09) ^ {(15-x)}. So:

P (X < 9) = 1 - P (X \geq 9) = 1 - [{15 \choose 9} (0.91)^{9}(0.09)^{6}+...+{ 15 \choose 15}(0.91)^{15}(0.09)^{0}] = 0.0002

P (X < 10) = 1 - P (X \geq 10) = 1 - [{15 \choose 10}(0.91)^{10}(0.09)^{5}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0013

P (X < 11) = 1 - P (X \geq 11) = 1 - [{15 \choose 11}(0.91)^{11}(0.09)^{4}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0082

P (X < 12) = 1- P (X \geq 12) = 1 - [{15 \choose 12}(0.91)^{12}(0.09)^{3}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0399

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

8 0
3 years ago
Please help evaluate?
Dominik [7]
3. 

4^3 is equal to 64. Therefor log4(64) must be equal to 3. 
3 0
3 years ago
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Answer:can u send a ss bc it wont load the photo

Step-by-step explanation:

8 0
3 years ago
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