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EastWind [94]
3 years ago
14

Given f(x) and g(x) = f(x) + k, look at the graph below and determine the value of k.

Mathematics
2 answers:
blagie [28]3 years ago
4 0

Answer:

k=4

Step-by-step explanation:

I took the test

Anton [14]3 years ago
3 0

Answer:

Given the graph f(x) = \frac{1}{3}x -2 and g(x) = \frac{1}{3}x + 3

We have to find the value of k;

Since, g(x) = f(x) +k

\frac{1}{3}x+3 = \frac{1}{3}x-2 +k

Subtract \frac{1}{3}x from both sides we get;

3 = -2 +k

Add 2 to both sides we get;

3+2 = -2 +k +2

Simplify:

5 = k

or

k = 5

Therefore, the value of k = 5


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astra-53 [7]

Answer:

<h2>108 yd²</h2>

Step-by-step explanation:

The formula of an area of a trapezoid:

A=\dfrac{b_1+b_2}{2}\cdot h

<em>b₁, b₂</em><em> - bases</em>

<em>h</em><em> - height</em>

From the picture we have

b_1=19yd,\ b_2=5yd,\ h=9yd

Substitute:

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3 years ago
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Answer:

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Step-by-step explanation:

By using the distributive property, you start by multiplying -2 and 6x which gets you -12x. You then multiply -2 and -y (in other words -y = -1y) so, -2* -y would get you 2 as a negative multiplied by a negative is a positive. So, adding them together would get your final answer: -2 (6x - y) = -12x + 2y

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The axis of symmetry for a function in the form f(x) = x2 + 4x − 5 is x = −2. What are the coordinates of the vertex of the grap
Studentka2010 [4]

Answer:

D) (-2,-9)

Step-by-step explanation:

<u>Vertex Form of a Vertical Parabola:</u>

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Axis of Symmetry -> x=h

Vertical Scale Factor -> a

  • To turn f(x)=x^2+4x-5 into vertex form, we need to complete the square on the right side
  • Therefore, if f(x)=0, then 0+9=x^2+4x-5+9 completes the square on the right side
  • This becomes 9=(x+2)^2
  • This means that our function in vertex form is f(x)=(x+2)^2-9

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