Thank you for posting your question here. I hope the answer below will help.
Vo=110 feet per second
h0=2 feet
So, h(t) = -16t^2 +110t +2
Take the derivative: h'(t) = 110 -32t
The maximum height will be at the inflection when the derivative crosses the x-axis aka when h'(t)=0.
So, set h'(t)=0 and solve for t:
0 = 110 -32t
-110 = -32t
t=3.4375
t=3.44 seconds
Answer: B
Step-by-step explanation:
<u>if 4w-1 ≥0</u> or w > 1/4 then
|4w-1|=4w-1
4w-1=5w+37 ==> w=-38 (exclude since not >1/4)
<u>else</u>
4w-1 < 0 or 4w <1 or w < 1/4
|4w-1|=-(4w-1)
-(4w-1)=5w+37
-4w+1=5w+37
9w=-36
w=-36/9
w=-4 ( which is < 1/4)
Sol={-4}
Answer B
<h2>Hey there!</h2>
<h3>Here's your required mode </h3>
<h3>Refer to the image above </h3>
<h3>And btw,in the earlier question I've done for mean also you can check that again which I've answered earlier. </h3>
<h2>Hope it helps</h2>
