7.14 mile per hour is how fast she ran
June 19th 2006 specifically a monday
400$
Explanation:
In 1992, the price is 28000$ and 9600$ in 1996 so in 4 years the value the car lost is 18400$
Dividing 18400 by 4 years we get 4600 depreciation value per year.
Between 1996 and 1998 there is 2 years
So in 1998 the value of the car will be:
9600 (value in 1996) - 2x4600 = 400$
Fractions,rats, and percents all interconnect. For ext,50%=11/2 =1:2
You want to find values of v (number of visors sold) and c (number of caps sold) that satisfy the equation
... 3v + 7c = 4480
In intercept form, this equation is
... v/(1493 1/3) + c/640 = 1 . . . . . divide by 4480
Among other things, this tells us one solution is
... (v, c) = (0, 640)
The least common multiple of 3 and 7 is 21, so decreasing the number of caps sold by some multiple of 3 and increasing the number of visors sold by that same multiple of 7 will result in another possible solution.
The largest multiple of 21 that is less than 4480 is 213. Another possible solution is (0 +213·7, 640 -213·3) = (1491, 1)
We can also pick some number in between, say using 100 as the multiple
... (0 +100·7, 640 -100·3) = (700, 340)
In summary, your three solutions could be
... (visors, caps) = (0, 640), (700, 340), (1491, 1)