How to find the answer ?

If the distance from 0 to x on a number line is equal to 5, then –5 + x = 0

harkovskaia [24]

In the problem -5+x=0, x=5

6 0

3 years ago

Identify holes in the graph of the function.

snow_lady [41]

Answer: x = 0

Step-by-step explanation:

The hole in the graph (a discontinuity) exist where the function doesn't exist. Because anything divided by zero is undefined, then the function would not exit at 0, thus having a hole/discontinuity.

7 0

3 years ago

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .

Subtract $-12x^2 -36x$ from both sides of the equation:

$38x + 7 = c(x + 3)$ .

By the same logic, $c = 38$ .

Hence the quotient would be $(4x^2 - 12x + 38)$ .

6 0

3 years ago

Find 0,8,3 round the nearest degree

MArishka [77]

The measure of $\theta$ is 68 degrees

<h3>How to solve the angle?</h3>

The complete question is in the attached image

The value of $\theta$ is calculate using the following cosine function

$\cos(\theta) = \frac 38$

Evaluate the quotient'

$\cos(\theta) = 0.375$

Take the arc cos of both sides

$\theta = \cos^{-1}(0.375)$

Evaluate the arc cos

$\theta = 67.97$

Approximate to the nearest degree

$\theta = 68$

Hence, the measure of $\theta$ is 68 degrees

Read more about right triangles at:

brainly.com/question/2437195

#SPJ1

3 0

2 years ago

(3.24 Socks in a drawer). In your sock drawer you have 4 blue, 5 gray, and 3 black socks. Half asleep one morning you grab 2 soc

irga5000 [103]

Answer:

a) Probability of ending up wearing 2 blue socks is 1/11.

b) Probability of ending up wearing no grey socks is 7/22.

c) Probability of ending up wearing at least 1 black sock is 5/11.

d) Probability of ending up wearing a green sock is 0.

e) Probability of ending up wearing matching socks is 19/66.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

In your sock drawer, you have 4 blue socks, 5 gray socks, and 3 black ones. Half asleep one morning, you grab 2 socks at random and put them on. Find the probability you end up wearing: a) 2 blue socks. b) no gray socks. c) at least 1 black sock. d) a green sock. e) matching socks.

The explanation of the answer is now given as follows:

The following are given in the question:

n(B) = number of Blue socks = 4

n(G) = number of Gray socks = 5

n(K) = number of black socks = 3

Therefore, we have:

n(T) = Total number of socks = n(B) + n(G) + n(K) = 4 + 5 + 3 = 12

To calculate a probability, the following formula for calculating probability is used:

Probability = Number of favorable outcomes / Number of total possible outcomes ……. (1)

Since this is a without replacement probability, we can now proceed as follows:

a) 2 blue socks

P(B) = Probability of ending up wearing 2 blue socks = ?

Probability of first pick = n(B) / n(T) = 4 / 12 = 1 / 3

Since it is without replacement, we have:

Probability of second pick = (n(B) – 1) / (n(T) – 1) = (4 – 1) / (12 – 1) = 3 / 11

P(B) = Probability of first pick * Probability of second pick = (1 / 3) * (3 / 11) = 1 / 11

b) no gray socks.

Number of favorable outcomes = n(B) + n(K) = 4 + 3 = 7

P(No G) = Probability of ending up wearing no gray socks = ?

Probability of first pick = Number of favorable outcomes / n(T) = 7 / 12

Since it is without replacement, we have:

Probability of second pick = (Number of favorable outcomes – 1) / (n(T) – 1) = (7 – 1) / (12 – 1) = 6 / 11

P(No G) = Probability of first pick * Probability of second pick = (7 / 12) * (6 / 11) = 7 / 22

c) at least 1 black sock.

Probability of at least one black sock = 1 - P(No K)

Number of favorable outcomes = n(B) + n(G) = 4 + 5 = 9

Probability of first pick = Number of favorable outcomes / n(T) = 9 / 12 = 3 /4

Since it is without replacement, we have:

Probability of second pick = (Number of favorable outcomes – 1) / (n(T) – 1) = (9 – 1) / (12 – 1) = 8 / 11

P(No K) = Probability of first pick * Probability of second pick = (3 / 4) * (8 / 11) = 24 / 44 = 6 / 11

Probability of at least one black sock = 1 - (6 / 11) = 5 / 11

d) a green sock.

n(Green) = number of Green socks = 0

Since, n(Green) = 0, it therefore implies that the probability of ending up wearing a green sock is 0.

e) matching socks.

This can be calculated using the following 4 steps:

Step 1: Calculation of the probability of matching blue socks

P(matching blue socks) = P(B) = 1 / 11

Step 2: Calculation of the probability of matching gray socks

P(matching green socks) = Probability of matching gray socks = ?

Probability of first pick = n(G) / n(T) = 5 / 12

Since it is without replacement, we have:

Probability of second pick = (n(G) – 1) / (n(T) – 1) = (5 – 1) / (12 – 1) = 4 / 11

P(matching gray socks = Probability of first pick * Probability of second pick = (5 / 12) * (4 / 11) = 20 / 132 = 5 / 33

Step 3: Calculation of the probability of matching black socks

P(matching black socks) = Probability of matching green socks = ?

Probability of first pick = n(K) / n(T) = 3 / 12 = 1 / 4

Since it is without replacement, we have:

Probability of second pick = (n(K) – 1) / (n(T) – 1) = (3 – 1) / (12 – 1) = 2 / 11

P(matching black socks) = Probability of first pick * Probability of second pick = (1 / 4) * (2 / 11) = 2 / 44 = 1 / 22

Step 4: Calculation of the probability of ending up wearing matching socks

P(matching socks) = Probability of ending up wearing matching socks = ?

P(matching socks) = P(matching blue socks) + P(matching grey socks) + P(matching black socks) = 1/11 + 5/33 + 1/22 = (6 + 10 + 3) / 66 = 19/66

6 0

2 years ago