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sergiy2304 [10]
3 years ago
9

How to find the answer ?

Mathematics
1 answer:
olasank [31]3 years ago
5 0

Answer:

girllll

Step-by-step explanation:

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A triangular prism has a Surface Area of 48.735 km2. The base of the prism is a triangle with a height of 3 and an unknown base.
xeze [42]
The surface area of the prism is equal to the summed up area of the faces of the triangular prism.

The bases of the prism would be triangles with an unknown base, b, and height of 3. The area of the base is calculated through the equation,
          A = bh/2
where b is base and h is height. Substituting the values,
       A = b(3)/2

Since there are two bases, the contribution of the triangles for the surface area is,
   2A = 3b

Next we calculate for the area of the triangle sides with length equal to b (same as the base of the triangle). 
   Area = b(12 km)
There are 3 sides such that the total area becomes,
   Area = 36b

Hence, the surface area is,
    48.735 km² = 3b + (36b)

The value of b from the equation is 1.25 km

<em>ANSWER: 1.25 km</em>
4 0
4 years ago
You want to place a towel bar that is 24 1⁄4 centimeters long in the center of a door that is 70 1⁄3 centimeters wide.
Ipatiy [6.2K]

Answer: <em>23 1/24 CM.</em>

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8 0
3 years ago
What is 6 3/4+1 5/8=
lara31 [8.8K]

Answer:

Step-by-step explanation:

6\frac{3}{4}+1\frac{5}{8}=6+1+\frac{3}{4}+\frac{5}{8}\\\\=7+\frac{3*2}{4*2}+\frac{5}{8}\\\\=7+\frac{6}{8}+\frac{5}{8}=7+\frac{6+5}{8}\\=7+\frac{11}{8}=7+1\frac{3}{8}=7+1+\frac{3}{8}\\\\=8\frac{3}{8}

7 0
4 years ago
a cyclist pedaling at a steady rate travels 30 miles with the wind. He can travel only 18 miles against the wind in the same amo
blondinia [14]
So.. traveling without the wind, let's say the pedalist has a speed of "r"

with the wind, the wind's rate is added to it, so, he's not going "r" fast, he's really going r+3 fast

against the wind, he's going r - 3 fast

notice, he covers 30 miles with it, and 18 miles against BUT the time for both ways is the same, say time "t"

now, recall your d = rt, distance = rate * time

thus \bf \begin{array}{lccclll}&#10;&distance(mi)&rate(mph)&time\\&#10;&-----&-----&-----\\&#10;\textit{with the wind}&30&r+3&t\\&#10;\textit{against the wind}&18&r-3&t&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;&#10;\begin{cases}&#10;30=(r+3)t\implies \frac{30}{r+3}=t\\\\&#10;18=(r-3)t\implies \frac{18}{r-3}=t&#10;\end{cases}\implies t=t\implies \cfrac{30}{r+3}=\cfrac{18}{r-3}

solve for "r"
4 0
3 years ago
PLEASE HELP FAST! I’ll give brainlist and extra points for right answer
il63 [147K]

Answer:  B

Step-by-step explanation:

5 0
3 years ago
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