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Lostsunrise [7]
2 years ago
10

81-1 1/5x < 55

Mathematics
1 answer:
Norma-Jean [14]2 years ago
8 0

Answer:

A. I guess

Step-by-step explanation:

not really sure

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How to figure this problem out
Mamont248 [21]
The answer is b because the problem is starting that
5 0
3 years ago
What is the product in lowest terms?
Alisiya [41]
-5/12 × 8/13

First, we need to start out by applying the multiplication rule towards fractions. If you haven't learned or don't remember the rules, you can always look up fraction rules. The rule is: a/b × c/d = ac/bd. Basically, we are combining the numerators and both of the denominators.
- \frac{5 \times 8}{12 \times 13}

Second, let's now multiply what we have in the fraction. (5 × 8 = 40) and (12 × 13 = 156). Doing so will create a new fraction for us to use.
-\frac{40}{156}

Third, now obviously, we can simplify the fraction we just got into lower terms. To do that, we have to collect the greatest common factor (GCF) of both the numerator and denominator and list their factors to find the common factor that is the greatest.

Factors of 40: 1, 2, 4, 5, 8, 10, 20, 40
Factors of 156: 1, 2, 3, 4, 6, 12, 13, 26, 39, 52, 78, 156

Out of the listed factors, which of those are the common ones? 1, 2, and 4 are the common factors. Since we are looking for the greatest common factor, it would be 4 since that is the higher number out of the commons. The GCF is 4.

Fourth, we can now divide our numerator (40) and our denominator (156) by the GCF we just found out, which was 4. 
40 \div 4 = 10  \\ 156 \div 4 = 39

Fifth, our last step is to create our new simplified fraction. All we have to do is take our new numerator and denominator to see the fraction. 

Answer in fraction form: \fbox {-10/39}
Answer in decimal form: \fbox {-0.2564}
4 0
3 years ago
A line segment BK is an angle bisector of ΔABC. A line KM intersects side BC such, that BM = MK. Prove: KM ∥ AB.
weqwewe [10]

Answer:

∠BKM= ∠ABK

Therefore AB ║KM (∵ ∠BKM= ∠ABK  and lies between AB and KM and BK is the transversal line)

m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)

Step-by-step explanation:

Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK

TO prove: KM ║AB

Now, As given in figure 1,

In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)

Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)

Now ∵ ∠MBK = ∠BKM

and  ∠ABK = ∠KBM

∴ ∠BKM= ∠ABK

Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)

Hence proved.  

8 0
3 years ago
Read 2 more answers
Solve the inequality 2x - 3
Crank
That's not an inequality. 
6 0
3 years ago
im so sad i literally cried for 10 min straight because i have three 70's on my grade progress report and my mom only wants 80's
givi [52]

Answer:

You shouldn't blame your mom. You are more than capable of getting 80's that is the bare minimum. Your mom does not want you to fail, try harder and get better grades. 70's are not the best

7 0
3 years ago
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