Answer:
a. -216, 0 real roots
Step-by-step explanation:
The discriminant of ...
ax² + bx + c = 0
is ...
d = b² -4ac
When we put your equation into the standard form shown above, we get ...
7n² +8n +10 = 0
Then we can identify a=7, b=8, c=10. The discriminant is then ...
d = 8² - 4·7·10 = 64 -280 = -216
___
The interpretation of the discriminant is ...
- < 0; no real roots (2 complex roots)
- = 0; one real root (multiplicity 2)
- > 0; 2 real roots
Your discriminant is -216, so there are 0 real roots.
The range for this function are 0,2,16,81
respectively
The correct question is
<span>The product of two consecutive positive integers is
11 more than their sum. find the integers.
Let
x-------> the first </span>positive integer
x+1-----> the second consecutive positive integer
we know that
x*(x+1)=11+(x+(x+1))----> x²+x=11+(2x+1)----> x²+x=2x+12
x²-x-12=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solution is
x=4
therefore
the numbers are
x=4
x+1=5
the answer isthe numbers are 4 and 5
Answer:
h(x-11)=-5
Step-by-step explanation:
just put the equetion from the top
h(x-11)=-5
me I know the answer. txt me or ask me