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Readme [11.4K]
2 years ago
10

If it takes a chicken and a half a day and a half to lay and egg and a half, then how many pancakes does it take to shingle a do

g house?

Mathematics
1 answer:
WINSTONCH [101]2 years ago
7 0

Answer:

14-23

Step-by-step explanation:

12

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What is the equation in point−slope form of the line passing through (−3, −4) and (0, 2)?
Nana76 [90]

Answer:

y = 2x + 2

Step-by-step explanation:

To find the slope we do (Y1 - Y2)/(X1-X2) aka rise over run

So, m = (-4 - 2) / (-3 - 0)

m = 2

Now we have y = 2x +b

Notice one of our points is (0,2)

Since the x value of that point is 0, it is the y intercept.

In the slope intercept form b = y-intercept

Therefore b = 2

So, y = 2x + 2

4 0
3 years ago
What’s 4,708.06 rounded to the nearest thousand?
STALIN [3.7K]

Answer:

when rounding anything that is or is greater than 5 you round up 1.

4,->7<-08.06

so rounding up 1, 4 would turn into 5.

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3 years ago
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The line inside this circle is its
Alex777 [14]
The answer will be (D)
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6 0
3 years ago
Kobe's overtime pay is $5 an hour more than his regular pay. He worked 8 hours at his regular wage and 3 hours at his overtime w
Fofino [41]

Answer: $9

Step-by-step explanation: 9•8=72

9+5=14

14•3=42

42+72=114

5 0
3 years ago
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N=4; 2i and 3i are zeros <br> f(-1)=50
Nonamiya [84]

Solution:- \text{Let f(x) be any nth degree polynomial with n=4}\\

\text{Given that 2i and 3i are the zeroes of f(x)}

\text{so (x-2i) and (x-3i) are factors of f(x)}

\text{Since 2i is a zero of f(x) then its conjugate -2i is also a zero of f(x)}

\Rightarrow(x+2i) \text{is a factor}\\\text{Similarly, conjugate of 3i is -3i is also a zero of f(x) }\\\Rightarrow(x+3i)\text{is a factor}\\\text{So , }\\f(x)=k(x-2i)(x+2i)(x-3i)(x+3i)\\=k(x^2-(2i)^2)(x^2-(3i)^2)\\=k(x^2-4i^2)(x^2-9i^2)\\=k(x^2+4)(x^2+9)\\=k(x^4+13x^2+36)\\\text{As given}\\f(-1)=50\\\Rightarrow k((-1)^4+13(-1)^2+36)=50\\\Rightarrow k(1+13+36)=50\\\Rightarrow k(50)=50\\\Rightarrow k=1\\\text{So by substituting k=1 in f(x) we get ,}\\f(x)=(x^4+13x^2+36)

6 0
3 years ago
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