Who can help me finish a course on edge ive done half of the course already its algebra !!

I need help finding the answer to this question on edge.

Aliun [14]

Answer:

6

Step-by-step explanation:

We need to evaluate :-

$\rm\implies \displaystyle\rm\sum^4_n (-1)^n (3n + 2 )$

Here the $\Sigma$ is the sum operator . And here we need to find the sum from n = 1 to n = 4 . We can write it as ,

$\rm\implies (-1)^1 ( 3*1 +2) + (-1)^2 ( 3*2+2) + (-1)^3(3*3+2) + (-1)^4(3*4+2)$

Now we know that for odd powers of -1 , we get -1 and for even powers we get 1 . Therefore ,

$\rm\implies -1 ( 3 + 2 ) + 1 (6+2)+-1(9+2)+1(12+2)$

Now add the terms inside the brackets and then multiply it with the number outside the bracket . We will get ,

$\rm\implies -1 * 5 + 1 * 8 + -1*11 + 1*14 \\\\\rm\implies -5 + 8 - 11 + 14 \\\\\rm\implies\boxed{\quad 6 \quad}$

Hence the required answer is 6.

6 0

2 years ago

Two third plush one half

Virty [35]

Two-thirds and one half is one and one sixth.

First, you times to denominators,

Then, you times the top by the bottom across, NOT BOTTOM!

Lastly, you add the top together then simplify, to get one and one sixth as your answer!

4 0

3 years ago

Read 2 more answers

If the length of AC equals 18, what is the length of the midsection DE

Free_Kalibri [48]

Answer:

The length of the midsegment is 9 ⇒ (B)

Step-by-step explanation:

In a triangle,

The midsegment is the segment which joining the midpoints of two opposite sides of it

The length of the midsegment is half the length of the third side in the triangle which opposite to it

Let us use this rule to solve our question

In Δ AC

∵ DE is the midsegment of it

∵ DE is opposite to the side AC

∴ The length of DE = 1/2 the length of AC

∵ The length of AC = 18

∴ The length of DE = 1/2 × 18

∴ The length of DE = 9

∴ The length of the midsegment is 9

The correct answer is B

7 0

3 years ago

PLSS HELP ASAP TYSM <33 SORRY I COULDN'T FIND SCIENCE LOLL

dimaraw [331]

Answer:

Rock D.

Step-by-step explanation:

We can assume that the force that the catapult does is always the same.

So, here we need to remember Newton's second law:

F = m*a

force equals mass times acceleration.

Where acceleration is the rate of change of the velocity.

So, if we want the rock to hit closer to the catapult, the rock must be less accelerated than rock B.

So, we can rewrite:

a = F/m

So, as larger is the mass of the rock, smaller will be the acceleration of the rock after it leaves the catapult (because the mass is in the denominator). So if we want to have a smaller acceleration, we need to choose a rock with a larger mass than rock B.

Assuming that the mass depends on the size, the only one that has a mass larger than rock B is rock D.

So we can assume that rock D is the correct option.

5 0

3 years ago

Creating and solving formulas for geometric series:mastery test

Levart [38]

Answer:

D. $y = 5\cdot \Sigma_{i=0}^{4} \left(\frac{1}{3} \right)^{i}$

Step-by-step explanation:

Let be $y = \Sigma_{i = 0}^{4} \left[5\cdot \left(\frac{1}{3} \right)^{i}\right]$ . To find the equivalent expression we must use the following property:

$y = c\cdot \Sigma_{i = 0}^{n} p(x) = \Sigma_{i=0}^{n} [c\cdot p(x)]$ (1)

Based on this fact, we find the following equivalence:

$y = 5\cdot \Sigma_{i=0}^{4} \left(\frac{1}{3} \right)^{i}$

Hence, the correct answer is D.

6 0

2 years ago