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Serggg [28]
3 years ago
15

Hey guys, I'm relearning some Algebra and was confused about this problem. In the equation, the problem was divided by 3. This m

akes sense because its easier to work with smaller numbers. However, after that the negative signs swapped. Why does this happen? I remember switching signs years ago when I learned it but now I can't remember the rule as to why. Thank you so much.

Mathematics
2 answers:
GuDViN [60]3 years ago
7 0

Answer:

That's optional

Step-by-step explanation:

Dealing with positive numbers is simpler that's why the equation was divided by -3.

Nonetheless, you can use:

-6x² - 5x + 1 = 0 too

You will get the same answer

D = (-5)² - 4(-6)(1)

D = 25 + 24 = 49

x = [-(-5) +/- sqrt(49)]/(2×-6)

x = [5 +/- 7]/(-12)

x = -2/-12 = ⅙

x = 12/-12 = -1

spayn [35]3 years ago
4 0

Answer and Step-by-step explanation:

The signs didn't really "swap". Instead, the whole function was divided by -1, or we could say the function was divided by -3. That would turn:

-18x² - 15x + 3 = 0

into

(-18 / -3)x² - (15 / -3)x + (3 / -3) = 0

6x² + 5x - 1 = 0

And that gives the "swapped signs".

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