Ratio of neutrons to protons and <span>number of electrons in the outer shell</span>
Answer:
1. Density of the rectangular prism is <u>20 g/cm3</u>
2. A material's ability to dissolve : <u>Soubility</u>
3. <u>Intensive property</u> : A physical property that is independent of sample size.
Explanation:
Volume of Prism is calculated by :
Length = 3 cm
Width = 2 cm
Height = 1 cm
V = 6 cm3
mass = 120 g
Density = 20 g/cm3
2.
<u>Solubility :</u>
- It is the chemical property of the substance.
- It shows the ability of the solute to dissolve in the solvent at a given temperature.
3.
<u>Intensive Properties:</u>
- These are bulk properties(Do not depend upon the amount of matter present)
- They are independent of sample size.
- Example : boiling point,melting point,temperature,refractive index
Answer:
Got your back
Explanation:
If the ions derived from different atoms are isoelectronic species, then they all have same number of electrons in their electronic shells and will have got same electronic configuration but their nuclear charge will differ because of their difference in number of protons in the nucleus. With increase in number of protons in the nucleus the electrons are more attracted towards nucleus thereby causing the decrease in ionic radius. On this principle our problem will be solved
The given ions are
7N-3
→no. of proton
=7
and
no of electron
=10
8O-2
→
no. of proton
=8
and
no of electron
=10
9F-→
no. of proton=9
and no of electron=10
11Na→
no. of proton=11
and no of electron=10
12 Mg-3→
no. of proton=12 and
no of electron=10
Hence the increasing order of ionic radius is
12Mg-3<11Na+<9F-<8O-2<7N-3
To rmember ->For isoelectronic species lower the nuclear charge higher the radius
Answer: denatured
Explanation:
To denature a proteins means to subject the protein to a condition that makes the protein to stop functioning as usual. This is usually due to a permanent change in the structure or shape of the protein. A protein may be denatured by change in pH, heat of binding of other molecules to the protein molecule.
