mole is the standardized form of molarity
Answer:
168°C is the melting point of your impure sample.
Explanation:
Melting point of pure camphor= T =179°C
Melting point of sample =
= ?
Depression in freezing point = 
Depression in freezing point is also given by formula:

= The freezing point depression constant
m = molality of the sample = 0.275 mol/kg
i = van't Hoff factor
We have:
= 40°C kg/mol
i = 1 ( non electrolyte)




168°C is the melting point of your impure sample.
Ernest Rutherford was a famous British physicist who lived and worked in the 19th and the first half of the 20th century. He is now considered to be the father of nuclear physics, given that he was the one responsible for figuring out about the nuclear structure of an atom (proton, electron, neutron) and about the nuclear processes in general. The element rutherfordium (Rf) is named after this scientist. When it comes to his personal life, his parents are both British, however, Ernest was born in New Zealand because his mom and dad before he was born. He worked as a professor in several universities, and was even knighted in 1914. He is a Nobel prize winner, which he won for Chemistry in 1908.
<span>(2.00 L) x (0.100 M HCl) / (1.50 M HCl) = 0.133 L</span>