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pentagon [3]
3 years ago
7

The scissor-tailed flycatcher is Oklahoma's state bird. If the combined weight of

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
8 0

Answer:

i dont know sorry

Step-by-step explanation:

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Find the volume of the square pyramid below.
miv72 [106K]

Hello!

\bf ANSWER

The volume of the square pyramid is approximately \boxed{ \bf 19.19~km^3}

____________________________________________________________

\bf EXPLANATION

V = a^{2}\frac{h}{3}

First, we must find the area of the square base.

A = l * w

A = 3.5 * 3.5

A = 12.25 km^2

The area of the base is 12.25 km^2. Now, multiply the base area by the perpendicular height. Then divide by 3.

V = (12.25 * 4.7) / 3

V = 19.1916666667

V ≈ 19.19 km^3



7 0
3 years ago
How do I solve this, it's not 10
guapka [62]

Answer:

26.7

Step-by-step explanation:

This is the answer because 26.7/20 = (16+26.7)/32

When two triangles are similar, it means their sides are also proportional. The reason why it is not ten is because you need to add 10 to 16 to the large triangle as well, which no longer makes it proportional.

To solve, you create a formula.

(16+x)/32=x/20

Multiply both sides by 32 to get rid of the 32 in the left side.

16+x=32x/20

Multiply both sides by 20 to get rid of the 20 right side.

320+20x=32x

-20x on both sides to get all the variables on one side and all the nukbers on the other.

320=12x

Divide both sides by 12 to get x by itself

x=26.66667

4 0
2 years ago
A model ship has a mast that is 7 inches tall. A right triangular sail goes from the top of the mast to 1 inch from the bottom o
dezoksy [38]

Answer:

12 square inches.

Step-by-step explanation:

Please consider the complete question.

A model ship has a mast that is 7 inches tall. A right triangular sail goes from the top of the mast to 1 inch from the bottom of the mast. The length of the base of the sail is 4 inches. The height of the sail is along the mast. Find the area of the sail.

The sail will form a right triangle with respect to mast, whose height is 6 inches and base is 4 inches as shown in the diagram.

The area of the sail will be equal to area of triangle.

\text{Area of triangle}=\frac{1}{2}(\text{Base}\times\text{Height})

\text{Area of triangle}=\frac{1}{2}(4\text{ in}\times6 \text{in})

\text{Area of triangle}=2\text{ in}\times 6 \text{in})

\text{Area of triangle}=12 \text{ in}^2

Therefore, the area of the sail is 12 square inches.

6 0
2 years ago
Two urns contain white balls and yellow balls. The first urn contains 2 white balls and 7 yellow balls and the second urn contai
Romashka [77]

-- The first urn has 9 balls in it all together, and 2 of them are white.
If you don't peek, then the prob of pulling out a white ball is  2/9 .

-- The second urn has 13 balls in it all together, and 3 of them are white.
If you don't peek, then the prob of pulling out a white ball is  3/13 .

-- The probability of being successful BOTH times is

        (2/9) x (3/13)  =  ( 6/117 )  =  about  0.0513  or  5.13% (rounded) 
4 0
3 years ago
Read 2 more answers
Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En
ArbitrLikvidat [17]

Answer:

a) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t, b) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t, c) x = 4\cdot \cos \left(t+\frac{\pi}{2}  \right), y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right).

Step-by-step explanation:

The equation of the circle is:

x^{2} + (y-1)^{2} = 16

After some algebraic and trigonometric handling:

\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1

\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t

Where:

\frac{x}{4} = \cos t

\frac{y-1}{4} = \sin t

Finally,

x = 4\cdot \cos t

y = 1 + 4\cdot \sin t

a) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t.

b) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t.

c) x = 4\cdot \cos t'', y = 1 + 4\cdot \sin t''

Where:

4\cdot \cos t' = 0

1 + 4\cdot \sin t' = 5

The solution is t' = \frac{\pi}{2}

The parametric equations are:

x = 4\cdot \cos \left(t+\frac{\pi}{2}  \right)

y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)

7 0
3 years ago
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