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2 years ago

13

A solar flare may cause charged particles to enter the earth's atmosphere. true false

1 answer:

svetoff [14.1K]2 years ago

4 0

Answer:

True

Explanation:

This is because the Earths ionisphere was distrubed which makes radio communications.

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Animals need various nutrients in order to live and grow. Nitrogen, for example, is a nutrient that is needed to form molecules

Ad libitum [116K]

Answer:

It's A

Explanation:

Animals get the nitrogen they need by eating plants or other animals that contain nitrogen. When organisms die, their bodies decompose bringing the nitrogen into soil on land or into ocean water. Bacteria alter the nitrogen into a form that plants are able to use.

8 0

2 years ago

Which of the following is a sign that a valley glacier has moved through an area? *

Dmitry_Shevchenko [17]

B. The rocks carried by the glacier would leave the marks

7 0

3 years ago

The half-life of cesium-137 is 30 years. Suppose we have a 180 mg sample. Find the mass that remains after t years. Let y(t) be

Stels [109]

Explanation:

1) Initial mass of the Cesium-137= $N_o$ = 180 mg

Mass of Cesium after time t = N

Formula used :

$N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}$

Half life of the cesium-137 = $t_{1/2}=30 years[p/tex]where,
[tex]N_o$ = initial mass of isotope

N = mass of the parent isotope left after the time, (t)

$t_{\frac{1}{2}}$ = half life of the isotope

$\lambda$ = rate constant

$N=N_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}$

Now put all the given values in this formula, we get

$N=180mg\times e^{-\frac{0.693}{30 years}\times t}$

Mass that remains after t years.

$N=180 mg\times e^{0.0231 year^{-1}\times t}$

Therefore, the parent isotope remain after one half life will be, 100 grams.

2)

t = 70 years

$N_o=180 mg$

$t_{1/2}= 30 yeras$

$N=180mg\times e^{-\frac{0.693}{30 years}\times 70 years}$

N = 35.73 mg

35.73 mg of cesium-137 will remain after 70 years.

3)

$N_o=180 mg$

$t_{1/2}= 30 yeras$

N = 1 mg

t = ?

$1 mg =180mg\times e^{-\frac{0.693}{30 years}\times t}$

$\frac{-30 year}{0.693}\times \ln \frac{1 mg}{180 mg}=t$

t = 224.80 years ≈ 225 years

After 225 years only 1 mg of cesium-137 will remain.

7 0

3 years ago

____H2 + ____O2 ---> ____H20<br><br> 2, 1, 1<br> 2, 2, 1<br> 2, 1, 2<br> 1, 2, 2

Tems11 [23]

2H2+O2----->2H2O. I hope this helps

6 0

3 years ago

Read 2 more answers

The basic structure of an amino acid contains the amine group, NH2, and a carboxylic acid group separated by one or more carbon

OLEGan [10]

The answer would be True

3 0

3 years ago