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Alex
2 years ago
15

When carbon-containing compounds are burned in a limited amount of air, some CO(g) as well as CO₂(g) is produced. A gaseous prod

uct mixture is 35.0 mass % CO and 65.0 mass % CO₂. What is the mass % of C in the mixture?
Chemistry
1 answer:
solong [7]2 years ago
3 0

Here, we are going to calculate the mass % of C in the mixture.

What is a Mixture?

A mixture is composed of one or more pure substances in varying composition. There are two types of mixtures: heterogeneous and homogeneous. Heterogeneous mixtures have visually distinguishable components, while homogeneous mixtures appear uniform throughout.

Given that,

The mass % of CO =35.0% =35.0 g in 100 g mixture

The mass % of CO2 = 65% =65 g in 100 g mixture

Therefore,

The mass of C from CO = 15.007 g C

Similarly,

The mass of C from CO2 = 17.738 g C

Thus, the total mass of C = 15.007 g+17.738 g =32.745 g

Therefore,

The mass % of C= 32.745% =32.7%

Thus, the mass % of C in the mixture is 32.7%

To learn more about carbon-containing compounds click on the link below:

brainly.com/question/13381262

#SPJ4

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Which of the following coefficients are needed to balance the combustion reaction of ethanol?
djyliett [7]
Answer is: d. 3,2,3.

Balanced chemical reaction: CH₃CH₂OH + 3O₂ → 2CO₂ + 3H₂O.
CH₃CH₂OH is ethanol.
O₂ is molecule of oxygen.
CO₂ is carbon(IV) oxide.
H₂O is water.
There are same number of atoms (oxygen, carbon and hydrogen) on both side of balanced chemical reaction:
2 atoms of carbon.
6 atoms of hydrogen.
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5 0
3 years ago
Quis critérios foram usadps por dobereiner em sua tentava de organiza os elementos químicos?
anyanavicka [17]

Döbereiner grouped the known elements into <em>triads</em> (sets of three) so that

• The <em>atomic mass of the middle element</em> was approximately the average    of the other two

• The <em>chemical properties of the middle element</em> were between those of the other two

• The <em>physical properties of the middle element</em> were between those of the other two

One example of a triad is Li – Na – K.

(a) Atomic mass of Na = 23.0 u

       Average atomic mass of Li and K = (6.9 u + 39.1 u)/2 = 46.0 u/2 = 23.0 u

(b) Li reacts slowly with water. Na reacts rapidly. Potassium reacts violently.

(c) Melting point of Na = 371 °C.

       Average melting point of Li and K = (454 °C + 330 °C)/2 = 784 °C/2

       = 392 °C

8 0
3 years ago
At an elevated temperature, Kp=4.2 x 10^-9 for the reaction 2HBr (g)---&gt; +H2(g) + Br2 (g). If the initial partial pressures o
Damm [24]

Answer : The partial pressure of H_2 at equilibrium is, 1.0 × 10⁻⁶

Explanation :

The partial pressure of HBr = 1.0\times 10^{-2}atm

The partial pressure of H_2 = 2.0\times 10^{-4}atm

The partial pressure of Br_2 = 2.0\times 10^{-4}atm

K_p=4.2\times 10^{-9}

The balanced equilibrium reaction is,

                                2HBr(g)\rightleftharpoons H_2(g)+Br_2(g)

Initial pressure    1.0×10⁻²       2.0×10⁻⁴      2.0×10⁻⁴

At eqm.            (1.0×10⁻²-2p)   (2.0×10⁻⁴+p)  (2.0×10⁻⁴+p)

The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{H_2})(p_{Br_2})}{(p_{HBr})^2}

Now put all the values in this expression, we get :

4.2\times 10^{-9}=\frac{(2.0\times 10^{-4}+p)(2.0\times 10^{-4}+p)}{(1.0\times 10^{-2}-2p)^2}

p=-1.99\times 10^{-4}

The partial pressure of H_2 at equilibrium = (2.0×10⁻⁴+(-1.99×10⁻⁴) )= 1.0 × 10⁻⁶

Therefore, the partial pressure of H_2 at equilibrium is, 1.0 × 10⁻⁶

4 0
4 years ago
1. What does it mean for a substance to be soluble?​
Anni [7]

Answer:

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Explanation:

3 0
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PSYCHO15rus [73]

Answer:

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Explanation:

5 0
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