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Alex
2 years ago
15

When carbon-containing compounds are burned in a limited amount of air, some CO(g) as well as CO₂(g) is produced. A gaseous prod

uct mixture is 35.0 mass % CO and 65.0 mass % CO₂. What is the mass % of C in the mixture?
Chemistry
1 answer:
solong [7]2 years ago
3 0

Here, we are going to calculate the mass % of C in the mixture.

What is a Mixture?

A mixture is composed of one or more pure substances in varying composition. There are two types of mixtures: heterogeneous and homogeneous. Heterogeneous mixtures have visually distinguishable components, while homogeneous mixtures appear uniform throughout.

Given that,

The mass % of CO =35.0% =35.0 g in 100 g mixture

The mass % of CO2 = 65% =65 g in 100 g mixture

Therefore,

The mass of C from CO = 15.007 g C

Similarly,

The mass of C from CO2 = 17.738 g C

Thus, the total mass of C = 15.007 g+17.738 g =32.745 g

Therefore,

The mass % of C= 32.745% =32.7%

Thus, the mass % of C in the mixture is 32.7%

To learn more about carbon-containing compounds click on the link below:

brainly.com/question/13381262

#SPJ4

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andrey2020 [161]
It was discovered in 1868.i hope this helps you .
4 0
3 years ago
If 700 g of water at 90 °C loses 27 kJ of heat, what is its final temperature?​
Phoenix [80]

Answer:

If 700 g of water at 90 °C loses 27 kJ of heat, its final temperature is 106.125 °C

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

In this way, between heat and temperature there is a direct proportional relationship (Two magnitudes are directly proportional when there is a constant so that when one of the magnitudes increases, the other also increases; and the same happens when either of the two decreases .). The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature, ΔT= Tfinal - Tinitial

In this case:

  • Q= 27 kJ= 27,000 J (being 1 kJ=1,000 J)
  • c=4.186 \frac{J}{g* C}
  • m=700 g
  • ΔT= Tfinal - Tinitial= Tfinal - 90 °C

Replacing:

27,000 J=4.186 \frac{J}{g* C}*400 g* (Tfinal - 90C)\\

Solving:

27,000 J=1,674.4 \frac{J}{C}* (Tfinal - 90C)

\frac{27,000 J}{1,674.4 \frac{J}{C}} =(Tfinal - 90C)

16.125 °C= Tfinal - 90 °C

Tfinal= 16.125 °C + 90 °C

Tfinal= 106.125 °C

<u><em>If 700 g of water at 90 °C loses 27 kJ of heat, its final temperature is 106.125 °C</em></u>

3 0
3 years ago
Discuss the significance of assigning an atomic mass of exactly 12 amu to the carbon-12 isotope.
evablogger [386]

Answer:

Cabon-12 has same average atomic weight and mass number.

Explanation:

carbon-12 has average atomic weight 12 amu and mass number of 12.

amu represents average of mass of a nucleon.

As carbon-12 has same average atomic mass and mass number therefore carbon-12 is a good standard to determine average mass of a nucleon.

Again, abundance of carbon-12 isotope is almost equal to 99%. Therefore fluctuation of average atomic weight from 12 amu is very very low.

So, carbon-12 is taken as a standard to determine mass of a nucleon.

Hence atomic mass of carbon-12 is 12 amu.

5 0
3 years ago
Given the equation I = Q/t, solve for t.
larisa86 [58]

Answer: t=\frac{Q}{I}

Explanation:

I=\frac{Q}{t}

Multiply by t on both sides.

t*I=\frac{Q}{t}*t

tI=Q

Now divide by I to isolate t.

\frac{tI}{I}=\frac{Q}{I}

t=\frac{Q}{I}

5 0
3 years ago
Why do ionic compounds have high melting points?
Vika [28.1K]
These oppositely charged compounds are strongly held by electrostatic forces of attraction as these be together for a long time the rise in temparature occurs so that the the melting points rises in them.
4 0
3 years ago
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