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3 years ago

Which one is correct

Chemistry

2 answers:

Elodia [21]3 years ago

6 0

The answer is C because wind turbines spin creating electrical energy from mechanical energy

Ksju [112]3 years ago

3 0

The answer is C, because wind turbines are used to produce electricity, and it's also the most safest way--but they are expensive.

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What is the molarity of a solution that contains 1000.0 mg of AgNO3 that has been dissolved in 500 mL of water

Vaselesa [24]

0.012moldm⁻³

Explanation:

Given parameters:

Mass of AgNO₃ = 1000mg

Volume of water = 500mL

Unknown:

Molarity of solution = ?

Solution:

The molarity of a solution is the number of moles of a solute dissolved in volume of solvent.

Molarity = $\frac{xnumber of moles}{Volume}$

Number of moles of AgNO₃ = ?

Number of moles = $\frac{mass}{molar mass}$

Molar mass of AgNO₃ = 108 + 14 + 3(16) = 170g/mol

convert mass to g;

1000mg = 1g

Number of moles = $\frac{1}{170}$ = 0.00588moles

convert the given volume to dm³;

1000mL = 1dm³;

500mL = 0.5dm³

Now solve;

Molarity = $\frac{0.00588}{0.5}$ = 0.012moldm⁻³

learn more:

Molarity brainly.com/question/9324116

#learnwithBrainly

4 0

3 years ago

Which is the molar mass of H2O?

Svetllana [295]

H=(2x1.008)=2.016
O= 15.999

15.999
+ 2.016
______
18.015 g/mol :)

3 0

3 years ago

Read 2 more answers

If 495 milliliters of carbon dioxide at 25°C and 101.3 kilopascals reacts with excess water, what is the theoretical yield of ca

postnew [5]

Answer:- 1.24 g

Solution:- The balanced equation for the formation of carbonic acid by the reaction of carbon dioxide with water is:

$CO_2+H_2O\rightarrow H_2CO_3$

From balanced equation, there is 1:1 mol ratio between carbon dioxide and carbonic acid. So, moles of carbonic acid will be equal to the moles of carbon dioxide used.

Moles of carbon dioxide can be calculated using ideal gas law equation as it's volume, temperature and pressure are given.

we need to convert mL to L, degree C to kelvin and kilopascals to atm.

$495mL(\frac{1L}{1000mL})$ = 0.495 L

25 + 273 = 298 K

$101.3kPa(\frac{1atm}{101.3kPa)})$

= 1 atm

Ideal gas law equation is:

PV = nRT

We want to find out the n, so let's rearrange this:

$n=\frac{PV}{RT}$

R is the universal gas constant and it's value is $\frac{0.0821atm.L}{mol.K}$ .

Let's pug in the values in the equation and solve it for n.

$n=\frac{1*0.495}{0.0821*298}$

n = 0.02 mol

To convert the moles to grams we multiply the moles by the molar mass of carbonic acid.

Molar mass of carbonic acid = 2(1.008)+12.01+3(16.00)

= 2.016+12.01+48.00

= 62.03 gram per mol (rounded to two decimal places)

Let's multiply the moles by molar mass:

$0.02mol(\frac{62.03g}{mol})$

= 1.24 g

So, the theoretical yield of carbonic acid is 1.24 g.

6 0

3 years ago

Read 2 more answers

Define Nuclear Fission and Fusion

ASHA 777 [7]

A nuclear reaction in which a heavy nuclear splits spontaneously or on impact with another particle with the release of energy- fission

A nuclear reaction in which atomic nucleus with the release of energy-fusion

The energy harnessed in nuclei is released in nuclear reaction. Fission is the splitting of a heavy nucleus into lighter nuclei and fusion is the combining of nuclei to form a bigger and heavier nucleus

6 0

3 years ago

Calculate the energy that is required to change 50.0 g ice at -30.0°C to a liquid at 73.0°C. The heat of fusion = 333 J/g, the h

OverLord2011 [107]

Answer:

There is 3.5*10^4 J of energy needed.

Explanation:

Step 1: Data given

Mass of ice at -30.0 °C = 50.0 grams

Final temperature = 73.0 °C

The heat of fusion = 333 J/g

the heat of vaporization = 2256 J/g

the specific heat capacity of ice = 2.06 J/gK

the specific heat capacity of liquid water = 4.184 J/gK

Step 2: Calculate the heat absorbed by ice

q = m*c*(T2-T1)

⇒ m = the mass of ice = 50.0 grams

⇒ c = the heat capacity of ice = 2.06 J/gK = 2.06 J/g°C

⇒ T2 = the fina ltemperature of ice = 0°C

⇒ T1 = the initial temperature of ice = -30.0°C

q = 50.0 * 2.06 J/g°C * 30 °C

q = 3090 J

Step 3: Calculate heat required to melt the ice at 0°C:

q = m*(heat of fusion)

q = 50.0* 333J/g

q = 16650 J

Step 4: Calculate the heat required to raise the temperature of water from 0°C to 73.0°C

q = m*c*(T2-T1)

⇒ mass = 50.0 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = T2-T1 = 73.0 - 0 = 73 °C

q = 50.0 * 4.184 * 73.0 = 15271.6 J

Step 5: Calculate the total energy

qtotal = 3090 + 16650 + 15271.6 = 35011.6 J = 3.5 * 10^4 J

There is 3.5*10^4 J of energy needed.

8 0

3 years ago