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UNO [17]
3 years ago
10

What will an object moving at a constant velocity do?

Chemistry
1 answer:
Len [333]3 years ago
3 0

Answer:B

Explanation: an object in motion will stay in motion until acted on by another force and an object in rest will stay in test until acted on by another force

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madam [21]
The surrounding ecosystem in and around the water
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3 years ago
A 40.0-mL sample of 0.100 M HNO2 (Ka = 4.6 x 10-4 .) is titrated with 0.200 M KOH. Calculate: a. the pH when no base is added b.
In-s [12.5K]

Answer:

a) 2.173

b) 20ml

c) 3.87

d) 4.35

e) 8.8

f) 12.45

Explanation:

chech the attachment for explanationns

4 0
3 years ago
Use the collision theory to explain how increasing the surface area of a solute will increase the rate of the dissolving process
Maksim231197 [3]
<span>More surface area --> more molecules of the solute in contact with the solvent --> more chance for a solvent molecule to collide with the solute molecules --> dissolves faster

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5 0
3 years ago
If the volume of a gas container at 32 degrees Celsius changes from 1.55 L to 755 mL, what will the final temperature be?
QveST [7]
So to solve this you need to know Charles’s law which is: V1/T1=V2/T2. Where T1 and V1 is the initial volume and Temperature and V2 and T2 is the temperature and volume afterwards. So first plug in the numbers you are given. V1= 1.55L T1= 32C° V2= 755mL T2=?. Since your volumes are two different units you change 755mL to be in L so that would be 0.755 L. And since your temp isn’t in Kelvin you do 273+32= 305K°. You then would rearrange your equation to solve for T2 which is V2T1/V1. Then you plug in your numbers (0.755L)(305K)/1.55L. Then you solve and would be 148.5645161 —> 1.49 x 10^2 K
4 0
2 years ago
1. An object was carefully weighed on three different balances. Each balance was zeroed
Hoochie [10]

Answer:

10.335

Explanation:

An object was carefully weighed on three different balances

Each of these balances were zeroed before weighing

The masses that were weighed are as follows

10.35 g , 10.355 g, 10.30 g

Therefore the average value of these measurements can be calculated as follows

The total number of mass is 3

= 10.30 + 10.355 + 10.30/3

= 31,005/3

= 10.335

Hence the average value of these measurements is 10.335

7 0
3 years ago
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