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lubasha [3.4K]
3 years ago
12

A sample of ethanol (C2H6O) has a mass of 0.2301 g. Complete combustion of this sample causes the temperature of a bomb calorime

ter to increase by 1.33°C. The calorimeter has a mass of 2.000 kg and a specific heat of 2.45 J/g•°C. How many moles of ethanol are present in the sample?
Chemistry
2 answers:
mojhsa [17]3 years ago
8 0

Answer:

the answer is 6.52 for the first one then the second one is 0.004993 and finally, 1,310

Hope this helps anyone

Please mark me as Brainliest

Keith_Richards [23]3 years ago
7 0

Answer:  4.994\times 10^{-3}  moles

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass , occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

Given mass of ethanol = 0.2301

Molar mass of ethanol = 46.07 g/mol

\text{Number of moles of ethanol}=\frac{0.2301g}{46.07g/mol}=4.994\times 10^{-3}

Thus there are 4.994\times 10^{-3}  moles of ethanol are present in the sample.

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A 0.175 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.27° in a 1-dm sample
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Answer:

The specific rotation of D is 11.60° mL/g dm

Explanation:

Given that:

The path length (l) =  1 dm

Observed rotation (∝) = + 0.27°

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Molar mass = 133.0 g/mol

Concentration in (g/mL) = 0.175 mol/L × 133.0 g/mol

Concentration in (g/mL) = 23.275 g/L

Since 1 L = 1000 mL

Concentration in (g/mL) = 0.023275 g/mL

The specific rotation [∝] = ∝/(1×c)

= 0.27°/( 1  dm ×  0.023275 g/mL )

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3 years ago
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Answer:

a) volume of ammonium iodide required =349 mL

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It shows that one mole of lead nitrate will react with two moles of ammonium iodide to give one mole of lead iodide.

Let us calculate the moles of lead nitrate taken in the solution.

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Moles of lead nitrate = 0.360 X 0.121 =0.0436 mol

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2.19 x 10^-12.

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