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Kobotan [32]
4 years ago
9

At what distance would radiation cease completely

Chemistry
1 answer:
Murrr4er [49]4 years ago
5 0
<span>depends on the type of radiation Alpha waves won't get very far Beta waves will get further Gamma waves and Xrays even further than beta</span>
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Which refers to substances that are complex molecules and contain carbon atoms bonded to hydrogen atoms?
victus00 [196]

Answer:

organic

Explanation:

Organic substances are those which contains covalently linked carbon to hydrogen (C-H) bonds in their structure. In other words, organic compounds or substances are uniquely composed of carbon and hydrogen atoms covalently linked together.

These substances usually contain a long chain of these bonds, hence, making them complex. Therefore, according to this question, substanves that are complex molecules and contain carbon atoms bonded to hydrogen atoms are referred to as ORGANIC SUBSTANCES.

5 0
3 years ago
The two major classes of telescopes are the _____ and the _____ telescope.
sukhopar [10]

Answer:

refractors and reflectors

Explanation:

4 0
3 years ago
Read the thesaurus entry and sentence.
tatiyna

Answer:noun

Explanation:

6 0
3 years ago
Read 2 more answers
Write the charge balance for a MgSO 4 and NaNO 3 solution that contains H + , OH − , Mg 2 + , HSO − 4 , SO 2 − 4 , MgHSO + 4 , M
irga5000 [103]

Answer :

MgSO_4 solution contains Mg^{2+} and SO_4^{2-}

NaNO_3 solution contains Na^{+} and NO_3^{-}

Explanation :

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

All the polyatomic ions always form an ionic compound.

Polyatomic ions : It is a charged species that composed of two or more atoms and these charged species are bonded by the covalent bond.

The given compounds are, MgSO_4 and NaNO_3

MgSO_4 is an ionic compound which is formed by the combination of Mg^{2+} cation and SO_4^{2-} anion.

and,

NaNO_3 is an ionic compound which is formed by the combination of Na^{+} cation and NO_3^{-} anion.

6 0
3 years ago
The force of attraction between a divalent cation and a divalent anion is 1.64 x 10-8 N. If the ionic radius of the cation is 0.
Elden [556K]

The radius of the anion is 7.413 nm

<h3>How to calculate the force of attraction between charges</h3>

The force of attraction (F) is given by the formula:

  • F = (1/4π∈r²)(Zc*e)(Za*e)

where:

∈ = permittivity of free space = 8.85*10⁻¹⁵ F/m

Zc = charge on the cation = +2

Zc = charge on the anion = -2

e = charge on an electron = 1.602 * 10⁻¹⁹ C

r = interionic distance

r = rc + ra

where rc and ra are the radius of the cation and anion respectively

F = 1.64 * 10⁻⁸ N

Therefore based on the equation of force of attraction:

1.64 *10⁻⁸ = [1/4π(8.85*10⁻¹⁵)r²](2 * 1.602*10⁻¹⁹)²

r² = 5.63 * 10⁻¹⁷

r = 7.50 nm

Since r = rc + ra

where rc = 0.087 nm

thus, ra = r - rc = 7.50 - 0.087

ra = 7.413 nm

Therefore, the radius of the anion is 7.413 nm

Learn more about ionic radius at: brainly.com/question/2279609

6 0
3 years ago
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