Answer:
29.41% of Calcium and 47.04% of Oxygen
Explanation:
The percent composition of an atom in a molecule is defined as 100 times the ratio between the mass of the atom and the mass of the molecule.
The mass of the molecule of the problem (Ore) is 46.28g. That means the percent composition of Calcium is:
13.61g / 46.28g * 100 = 29.41% of Calcium
And percent composition of Oxygen is:
21.77g / 46.28g * 100 = 47.04% of Oxygen
Answer:
she should not have multiplied the sulfur atoms by the subscript 4
Explanation:
The chemical could have more or less of a reaction to the other chemicals in the experiment
Answer:
of carbon dioxide gas.
Explanation:
Average distance covered by Americans in a day= 
1 day = 24 × 60 min = 1,440 min
Average distance covered by Americans in a minute= 
Average mileage of the car = 20 miles/gal = 32.18 km/gal
1 mile = 1.609 km
20 miles = 20 × 1.609 km = 32.18 km
Volume of gasoline used in minute = 


(1 L = 1000 mL)

Mass of 86,320.00 gallons of gasoline = m
Density of the gasoline = d = 



1 kilogram of gasoline gives 3 kg of carbon dioxde gas .
Then 303,882.84649 kg of gasoline will give :
of carbon dioxide gas.
Answer:
See explaination
Explanation:
The invariant mass of an electron is approximately9. 109×10−31 kilograms, or5. 489×10−4 atomic mass units. On the basis of Einstein's principle of mass–energy equivalence, this mass corresponds to a rest energy of 0.511 MeV.
Check attachment for further solution to the exercise.