Na more reactive than Cu
<h3>Further explanation</h3>
Given
Copper in a solution of NaCl
Required
The displacement theory
Solution
A single replacement reaction is a chemical reaction in which one element replaces the other elements of a compound to produce new elements and compounds
Not all of these reactions can occur. We can use the activity series, which is a list of elements that can replace other elements below / to the right of them in a single replacement reaction.
The voltaic series:
<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe²⁺-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Fe³⁺-Ag-Pt-Au </em>
The electrode which is easier to reduce than the hydrogen (H2) electrode has a positive sign (E red= +) and is located to the right of the voltaic series (right of H)
The electrode which is easier to oxidize than the hydrogen (H2) electrode and is difficult to experience reduction has a negative sign (E red= -) and is located to the left of the voltaic series (left of H)
Reaction
Cu + NaCl≠
The existing copper element can not replace the sodium element, which is on the left side so the reaction will not occur.
But if it is reversed, then a reaction can occur
2 Na + CuCl2 → Cu + 2 NaCl
Answer:
tensile strength, elongation, flexural strength, and impact resistance.
Explanation:
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The following: Jupiter, Saturn, Uranus, or Neptune.
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any of the planets Jupiter, Saturn, Uranus, and Neptune whose orbits lie beyond the asteroid belt.
Answer:
Ka3 for the triprotic acid is 7.69*10^-11
Explanation:
Step 1: Data given
Ka1 = 0.0053
Ka2 = 1.5 * 10^-7
pH at the second equivalence point = 8.469
Step 2: Calculate Ka3
pKa = -log (Ka2) = 6.824
The pH at the second equivalence point (8.469) will be the average of pKa2 and pKa3. So,
8.469 = (6.824 + pKa3) / 2
pKa3 = 10.114
Ka3 = 10^-10.114 = 7.69*10^-11
Ka3 for the triprotic acid is 7.69*10^-11
