Answer:
4 Fe + 3 O2 = 2 Fe2O3
Explanation:
In order to balance the equation, there should be equal number of iron atoms (Fe) and oxygen atoms (O2) in Iron(III) oxide (Fe2O3).
Since there are two atoms of Oxygen in 1 oxygen molecule and 3 atoms of Oxygen in 1 Iron Oxide, the least common multiples of the total oxygen atoms which would equal each other is 6 atoms of Oxygen. This results in 3 molecules of O2 and 2 molecules of Fe2O3.
In order to balance out the amount of iron in iron oxide, you must then calculate the total iron atoms in iron oxide; since there are 2 atoms of Fe in each molecule of Iron Oxide and there is 2 molecules of Fe2O3, the total is 2*2 = 4 atoms of iron, Fe.
In order to get 4 atoms of iron from molecules of Fe, you need 4 molecules of Fe, since each molecule contains 1 Fe.
Explanation:
Ionization reactions are reactions that involve an electrically neutral atom or molecule be converted into electrically charged atom or molecule (ions).
Ions are recognized by the (⁺) and (⁻) signs.
First Reaction: Ions are formed so this option is correct.
Second Reaction: Ions are formed so this option is correct.
Third Reaction: This option is wrong. No ions are formed.
Fourth Reaction: Ions are formed so this option is correct.
Fifth Reaction: Ions are formed so this option is correct.
Answer: The rate of the loss of 
is 0.52M/s
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
Rate of disappearance of =![-\frac{1d[O_3]}{2dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BO_3%5D%7D%7B2dt%7D)
Rate of formation of 
=![+\frac{1d[O_2]}{3dt}](https://tex.z-dn.net/?f=%2B%5Cfrac%7B1d%5BO_2%5D%7D%7B3dt%7D)
![-\frac{1d[O_3]}{2dt}=+\frac{1d[O_2]}{3dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BO_3%5D%7D%7B2dt%7D%3D%2B%5Cfrac%7B1d%5BO_2%5D%7D%7B3dt%7D)
Rate of formation of = 
Thus Rate of disappearance of =![\frac{2d[O_2]}{3dt}=\frac{2}{3}\times 7.78\times 10^{-1}M/s=0.52M/s](https://tex.z-dn.net/?f=%5Cfrac%7B2d%5BO_2%5D%7D%7B3dt%7D%3D%5Cfrac%7B2%7D%7B3%7D%5Ctimes%207.78%5Ctimes%2010%5E%7B-1%7DM%2Fs%3D0.52M%2Fs)
Answer:
Yes, it is.
Explanation:
A buffer is a solution in which a weak acid is in equilibrium with its conjugate base, or a weak base is in equilibrium with its conjugate acid. Because of the equilibrium, when an acid or a base is added to it, the pH remains almost unaltered.
But the buffer has a limit, generally, it works well in the range of pKa - 1 to pKa +1. The pKa value indicates the force of the acid, and it's calculated by -logKa, where Ka is the equilibrium constant of the acid. The pKa value of citric acid is 6.86, does a buffer of it can function well at pH 7.
The successive deprotonations of the acid increase the "-" charge density on the resulting anion, in this case, the carboxylate groups. This is unfavorable electrostatic repulsions between the anions which reduces the likelihood that a proton would dissociate. So, it's more favorable for the proton to remain bound to reduce unfavorable charge repulsion. Because of that, the equilibrium can be achieved.
Answer:
Iron (Fe)
Explanation:
The number of electrons (-) is usually the same as the number of protons (+) in the atom of the element (unless it is an ion).
The element described has 26 electrons, so we can assume that it has 26 protons as well. The number of protons in an atom is the atomic number of element that the atom is.
Element 26 on the PTE is Iron (Fe), which does rust (oxidation) in air and water.
