Question

Find the missing side lengths and leave the radicals in the simplest form.

Answer 1

Answer:

$y=\frac{9\sqrt{2} }{2}$ and x=9

Step-by-step explanation:

We can see that the triangle is a special triangle or isosceles triangle meaning that two angles/ two sides are the same.

$y=\frac{9\sqrt{2} }{2}$

To solve for x use Pythagorean Theorem.

a^2 + b^2 = c^2.

$\frac{9\sqrt{2} }{2} +\frac{9\sqrt{2} }{2}=x^2\\\\\frac{81}{2} +\frac{81}{2} =x^2\\\\\frac{162}{2} =x^2\\\\x=\sqrt{\frac{162}{2} } =\sqrt{81} =9\\\\x=9$