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Lina20 [59]
3 years ago
11

Evaluate ∫ e3x dx. ExplAin answers please

Mathematics
1 answer:
Rufina [12.5K]3 years ago
7 0
Hello,
PLease, see the attached file.
Thanks.

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Use three fours to make 11.
mr Goodwill [35]
4 + 4 + 4 - 1 = 11? Was it supposed to be an equation? I am confused.
7 0
3 years ago
An acute angle theta is in a right triangle with cos theta = 5/6. What is the value of sec theta?
pochemuha

Answer:

  • sec=1/cos

Step-by-step explanation:6/5

5 0
3 years ago
Annie traveled 5 times the sum of the number of hours Brian traveled and 2. together they traveled 20 hours. find the number of
kari74 [83]
Well There isn't enough evidence to tell how many hours each of them worked. Yu stated how long they each traveled separately but did not state the amount of hours worked, or any proof for it.

But Assuming that by worked you mean traveled.
Annie traveled 5 times the sum of the number of hours Brian traveled and 2. together they traveled 20 hours. find the number of hours each person worked.So 20 is 6 times the number of hours Annie & Brian Worked + 10
(From the 10 extra hours Annie worked from +2)
10/6=1 hour and 40 min
So Brain worked/traveled for 1 hour and 40 minuets. 
Then we find Annie's time. Add 2 hours to 1 hour and 40 and you get
3 hours 40 times that by 5 and you get 18 hours and 20 min
So Annie worked/traveled for 18 hours and 20 min
I hope this helped
4 0
3 years ago
Give an example of a polynomial that has the asymptotes of x=5 and y=0.5
BaLLatris [955]
(x²+4x+3)/2(x²-10x+25)

the horizontal asymptote when the numerator and the denominator have the same degree (in this case, both of a degree of 2) is ration of the coefficients of the numerator and denominator. In this case, the coefficient for numerator x² is 1, and the coefficient for the denominator 2x² is 2, so the horizontal asymptote is y=1/2=0.5

the vertical asymptote is the x value. the denominator cannot be zero, if x²-10x+25=0, x would be 5, so the vertical asymptote is x=5 

this is just one example. There can be others:
(2x²+5x+2)/[(4x-7)(x-5)]  for another example, but this example has a second vertical asymptote 4x-7=0 =>x=7/4
5 0
3 years ago
Find all solutions to the equation (sinx-cosx)^2=1
svetoff [14.1K]

Answer:

x=\dfrac{\pi k}{2},\ k\in Z.

Step-by-step explanation:

Simplify the equation (\sin x-\cos x)^2=1:

\sin^2 x-2\sin x\cos x+\cos ^2x=1,\\ \\ (\sin^2x+\cos^2x)-2\sin x\cos x=1.\\

Since

\sin^2 x+\cos^2 x=1

and

2\sin x\cos x=\sin 2x,

we have

1-\sin 2x=1,\\ \\\sin 2x=0,\\ \\2x=\pi k,\ k\in Z,\\ \\x=\dfrac{\pi k}{2},\ k\in Z.

8 0
3 years ago
Read 2 more answers
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