All categories

3 years ago

Evaluate ∫ e3x dx. ExplAin answers please

Mathematics

1 answer:

Rufina [12.5K]3 years ago

7 0

Hello,
PLease, see the attached file.
Thanks.

You might be interested in

So when you add 3+4 you get 7, but what if you divide 7 by 4? Do you still get 3?

krek1111 [17]

No you wouldn’t it would be a different answer

7 0

2 years ago

Read 2 more answers

Multiply (2.0 ⋅ 10−4) ⋅ (3.1 ⋅ 10−20). Express the answer in scientific notation. The options are:

Mkey [24]

(2.0×10^-4)×(3.1×10^-20)
=(2.0×3.1)×(10^4×10^-20)
=6.2×10^(-4+(-20))
=6.2×10^-24. Hope it help!

3 0

2 years ago

During a tournament, a batting cage can be used for $5.00 for 50 pitches. If all 192 players use the cage one time, how much mon

Fynjy0 [20]

First, we have to find the rate:
500/50
100/10
10/1
10 cents a pitch:
129 * 10 = 1290
It will cost $12.90

7 0

2 years ago

Classify the expression: −2x

ValentinkaMS [17]

Answer:

classical music

Step-by-step explanation:

i suggest beetoven for classicla and for rock the rock

4 0

3 years ago

After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i

Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume ( $V$ ) is calculated by:

$V = \frac{4\pi}{3}\cdot R^{3}$

Where $R$ is the radius of the tumor.

The percentage decrease in the volume of the tumor ( $\%V$ ) is expressed by:

$\%V = \frac{\Delta V}{V_{o}} \times 100\,\%$

Where:

$\Delta V$ - Absolute decrease in the volume of the tumor.

$V_{o}$ - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

$\Delta V = V_{o}-V_{f}$

$\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})$

The percentage decrease is finally simplified:

$\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%$

Given that $R_{o} = R$ and $R_{f} = 0.77\cdot R$ , the percentage decrease in the volume of tumor is:

$\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%$

$\%V = 54.34\,\%$

The volume of the tumor experimented a decrease of 54.34 percent.

5 0

3 years ago