Answer:
The answer is the last one (32x^7y^15)
You can bring x to the second power (x^2) because (x) is basically x^1. This is a basic exponent rule. (x^m)^n = x^m times n.
Then you can apply this rule to (2xy^3)^5. First you bring two to the fifth power and get 32. Then you bring x^5 according to the rule. Then you bring y^15, also because of the rule.
Now you have:
x^2 times 32x^5y^15
Now you just multiply the like terms together (x^2 and x^5)
When you multiply two exponents with the same base, you add the exponents together: a^n times a^m = a^n+m.
So you end up with 32x^7y^15
Answer:
y = 12
Step-by-step explanation:
∵ m∠ABC = 40
∵ BD ray is the bisector of ∠ABC
∴ m∠ABD = m∠CBD = 20
In 2 Δ BAD and BCD:
∵ m∠BAD = m∠BCD = 90°
∵ m∠ABD = m∠CBD = 20°
∵ BD is a common side in the two triangles
∴ ΔABD congruent to ΔCBD⇒(AAS)
∴ AD = CD
∴ 3y + 6 = 5y - 18
∴ 5y - 3y = 6 + 18
∴ 2y = 24
∴ y = 24/2 = 12
Answer:
A.) the SSS Postulate
Step-by-step explanation:
Two sides of each triangle are marked congruent, and the third side is shared by the triangles. Hence, all three sides are congruent, and the SSS Postulate applies.
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