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allochka39001 [22]
1 year ago
9

How do you find a 180 degree angle?

Mathematics
1 answer:
Tom [10]1 year ago
5 0

180° angle is a straight line

hope it helps....!!!

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HELP ASAP ITS DUE TOMORROW PLS!!!!!
Gelneren [198K]

Answer:

Im pretty sure the answe is C

Step-by-step explanation:

im very bad at explaining im sorry

7 0
3 years ago
I need help with this one
Butoxors [25]

Answer:

2 2/3

Step-by-step explanation:

8 0
2 years ago
What is the equation of the line AB, if it passes through (-4,0), and is parallel to the line
Karo-lina-s [1.5K]

Rewriting the equation of the given line in slope-intercept form,

-x-4y=1\\\\-4y=x+1\\\\4y=-x-1\\\\y=-\frac{1}{4}x-\frac{1}{4}

From this, we know the slope of the given line is -1/4.

Since parallel lines have the same slope, we know the line whose equation we want to find has a slope of -1/4.

Substituting into point-slope form,

y=-\frac{1}{4}(x+4)\\\\\boxed{y=-\frac{1}{4}x-1}

6 0
1 year ago
3. A rare species of aquatic insect was discovered in the Amazon rainforest. To protect the species, environmentalists declared
navik [9.2K]

The number of months until the insect population reaches 40 thousand is 14.29 months and the limiting factor on the insect population as time progresses is 250 thousands.

Given that population P(t) (in thousands) of insects in t months after being transplanted is P(t)=(50(1+0.05t))/(2+0.01t).

(a) Firstly, we will find the number of months until the insect population reaches 40 thousand by equating the given population expression with 40, we get

P(t)=40

(50(1+0.05t))/(2+0.01t)=40

Cross multiply both sides, we get

50(1+0.05t)=40(2+0.01t)

Apply the distributive property a(b+c)=ab+ac, we get

50+2.5t=80+0.4t

Subtract 0.4t and 50 from both sides, we get

50+2.5t-0.4t-50=80+0.4t-0.4t-50

2.1t=30

Divide both sides with 2.1, we get

t=14.29 months

(b) Now, we will find the limiting factor on the insect population as time progresses by taking limit on both sides with t→∞, we get

\begin{aligned}\lim_{t \rightarrow \infty}P(t)&=\lim_{t \rightarrow \infty}\frac{50(1+0.05t)}{2+0.01t}\\ &=\lim_{t \rightarrow \infty}\frac{50(\frac{1}{t}+0.05)}{\frac{2}{t}+0.01}\\ &=50\times \frac{0.05}{0.01}\\ &=250\end

(c) Further, we will sketch the graph of the function using the window 0≤t≤700 and 0≤p(t)≤700 as shown in the figure.

Hence, when the population P(t) (in thousands) of insects in t months after being transplanted by P(t)=(50(1+0.05t))/(2+0.01t) then the number of months until the insect population reaches 40 thousand 14.29 months and the limiting factor on the insect population is 250 thousand and the graph is shown in the figure.

Learn more about limiting factor from here brainly.com/question/18415071.

#SPJ1

8 0
2 years ago
Simplify the expression by combining like terms -3x - 8 + 7x - 1
natulia [17]

Answer:

4x-9.

Step-by-step explanation:

-3x - 8 + 7x - 1

7x -3x=4x.

-8 -1= - 9.

4x-9

8 0
2 years ago
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