First you need to multiply the number on the outside of the parentheses to what's inside. Then you need to subtract 1440 from both sides. After that you need to get all of the u's on one side so you subtract 256u from -160u and then you divide 832 by 96.
You know where the glacier is now, and how far it moves in
one year. The question is asking how close to the sea it will be
after many years.
Step-1 ... you have to find out how many years
Step-2 ... you have to figure out how far it moves in that many years
Step-3 ... you have to figure out where it is after it moves that far
The first time I worked this problem, I left out the most important
step ... READ the problem carefully and make SURE you know
the real question. The first time I worked the problem, I thought
I was done after Step-2.
============================
Step-1: How many years is it from 2010 to 2030 ?
(2030 - 2010) = 20 years .
Step-2: How far will the glacier move in 20 years ?
It moves 0.004 mile in 1 year.
In 20 years, it moves 0.004 mile 20 times
0.004 x 20 = 0.08 mile
Step-3: How far will it be from the sea after all those years ?
In 2010, when we started watching it, it was 6.9 miles
from the sea.
The glacier moves toward the sea.
In 20 years, it will be 0.08 mile closer to the sea.
How close will it be ?
6.9 miles - 0.08 mile = 6.82 miles (if it doesn't melt)
Answer:
y = - 2x + 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
here m = - 2 and c = 3, hence
y = - 2x + 3 ← equation in slope- intercept form
12%
$68 - 59.9 = $8.1
$8.1/$68 = 0.11911764705
0.11911764705 x100 = 11.911764705
11.911764705 is rounded up to 12
12%
Answer:
Step-by-step explanation:
If you foil this equation you will get:
And by dividing it, you will get;
That is your answer!
