The answer is a.0.32 km.
The speed that a tsunami can travel is modeled by the equation is s = 356√d.
It is given:
s = 200 km/h
d = ?
Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562
Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32
Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
Answer:
see explanation
Step-by-step explanation:
The area (A) of the square = s² ( s is the measure of the side )
Here s = x + 2 and A = 7 , thus
(x + 2)² = 7 ← expand left side using FOIL
x² + 4x + 4 = 7 ( subtract 4 from both sides )
x² + 4x = 3 ← as required
Answer:
<h2>y = -70</h2>
Step-by-step explanation:
180-156= 24
24°!!
hope this helped u<3
As the question say this problem is a practice of the law of cosines!
The law of cosine: c^2=a^2+b^2-2ab*cos*c for any side a, b and c
The law can also be written as c=sqrt(a^2+b^2-2abcosc)
Now use this formula!(note cos 100 degrees is about 0.8623)
c=sqrt(15^2+16^2-2*15*16*cos100)
solving this we can MN is about 23.75
Round this to the nearest tenths now!
We get 23.8!
Thus the answer is D
