Question

The nth term of a sequence is 8(n+3) what are the first four terms?

Answer 1

Answer:

32, 40, 48, 56

Step-by-step explanation:

$a_n= 8(n+3)...(given) \\\\ a_1= 8(1+3) = 8 \times 4 = 32 \\ \\ \: a_2= 8(2+3) = 8 \times 5 = 40 \\ \\ a_3= 8(3+3) = 8 \times 6 = 48 \\ \\ a_4= 8(4+3) = 8 \times 7 = 56$