Answer:
a) 
is the speed of each proton
b) 
Explanation:
Given:
radius of path of motion, 
we know charge on protons, 
magnetic field strength, 
we've mass of proton, 
a)
From the equivalence of magnetic force and the centripetal force on the proton:
where:
v = speed of the proton
is the speed of each proton
b)
Now the centripetal force on each proton:
The right<span> at +20.0 </span>cm/s makes<span> an </span>elastic head<span>-on </span>collision<span> with a 10.0 </span>g object<span> that </span>makes<span> an</span>elastic head<span>-on </span>collision<span> with a 10.0 </span>g object<span> that is </span>initially<span> at </span>rest<span>.(b) Find the fraction of the </span>initial<span>kinetic energy transferred to the 10.0 </span>g object<span>.of small </span>mass<span> before and </span>after collision; V=velocity<span> of big </span>mass after collision<span>.</span>
Let distance be x.
Time in going, t 1 = x/50
Time in coming, t 2 = x/40
Total time T = x/40 +x/50 = 9x/200
Average speed = total distance/ total time
=( x+x)/(9x/200)= 2x ×200/9x = 400/9 = 44.44 km/h
Answer:
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I Hope this helps!
Sincerely; Victoria<3
Explanation:
