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Oliga [24]
3 years ago
7

What is the acceleration of an object going from O m/s to 25 m/s in 5s?

Physics
2 answers:
kobusy [5.1K]3 years ago
8 0

Answer:

5m/s^2 is the acceleration.

Bingel [31]3 years ago
5 0

Answer:

\boxed {\boxed {\sf a= 5 \ m/s^2}}

Explanation:

Acceleration is the change in speed over time.

a=\frac{ v_f-v_i}{t}

The object accelerates from 0 meters per second to 25 meters per second in 5 seconds.

v_f= 25 \ m/s\\v_i= 0 \ m/s \\t= 5 \ s

Substitute the values into the formula.

a=\frac{ 25 \ m/s -0 m/s }{ 5 \ s}

Solve the numerator.

a=\frac{25 \ m/s}{5 \ s}

Divide

a= 5 \ m/s/s= 5 \ m/s^2

The object's acceleration is <u>5 meters per square second.</u>

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A scientific hypothesis can become a theory if
viktelen [127]

Answer: If, enough evidence accumulates to support a hypothesis, it moves to the next step (known as a theory) in the scientific method and becomes accepted as a valid explanation of a phenomenon.

Explanation:  a scientific theory is the framework for observations and facts.

( hope this helped )

5 0
3 years ago
Why is rock away from ocean ridges older? Is it because if the rocks are away from cracks in the crust, there is no way for any
andreyandreev [35.5K]

Answer:

the rocks are away from cracks in the crust

Explanation:

   The new crust is pushed away from the Ocean Ridge in both directions as newer crust is formed. This is called sea floor spreading. The crust that makes up the sea floor starts to have time to accumulate a layer of sediments as it gets older and moves away from the Ocean Ridge.

6 0
2 years ago
Read 2 more answers
A 5 N force pushes on the right side of a box. At the same time, a 10 N force pushes on the left side of the box. What happens t
notka56 [123]
The resultant force is 5N.So the box moves to right with constant acceleration.
8 0
4 years ago
Read 2 more answers
According to Newton's Universal Law of Gravitation, when the distance between two interacting objects doubles, the gravitational
maksim [4K]

Answer:

<em>If the distance doubles, the gravitational force is divided by 4</em>

Explanation:

<u>Newton’s Universal Law of Gravitation </u>

Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.

\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}

Where:

m1 = mass of object 1

m2 = mass of object 2

r     = distance between the objects' center of masses

G   = gravitational constant: 6.67\cdot 10^{-11}~Nw*m^2/Kg^2

If the distance between the interacting objects doubles to 2r, the new force F' is:

\displaystyle F'=G{\frac {m_{1}m_{2}}{(2r)^{2}}}

Operating:

\displaystyle F'=\frac{1}{4}G{\frac {m_{1}m_{2}}{r^{2}}}

Substituting the original value of F:

\displaystyle F'=\frac{1}{4}F

If the distance doubles, the gravitational force is divided by 4

5 0
3 years ago
A car is traveling at 20 m/s and a dog runs out in front
Pani-rosa [81]

Answer:

Below

Explanation:

To find the acceleration of the car you can use this formula and rearrange :

     vf = vi + at

We know that our time is 2 seconds, our initial velocity, vi, is 20 m/s, and our final velocity vf is 0 because the car comes to a stop before hitting the dog.

So we can just go ahead and plug in these values into the equation above :

     0m/s = 20m/s + (a)(2s)

     -20m/s = 2s(a)

Divide both sides by 2

     -10m/s^2 = a

Therefore the acceleration of the car is -10m/s^2 [forward]

     You could also write this as 10m/s^2 [back]

Hope this helps! Best of luck <3

8 0
3 years ago
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