Answer:
Explanation:
Volume of asteroid = 4/3 x π x 160³
= 17.15 x 10⁶
mass = volume x density
= 17.15 x 10⁶ x 2600
= 445.9 x 10⁸ kg
kinetic energy
= 1/2 x 445.9 x 10⁸ x( 12.6 )² x 10⁶
= 35.4 x 10¹⁷ J .
2 )
energy of 15 megaton
= 4.184 x 10¹⁵ x 15 J
= 62.76 x 10¹⁵ J
No of bombs required
= 35.4 x 10¹⁷ / 62.76 x 10¹⁵
= 56.4 Bombs .
#1
Jill and Scott both moves for 30 minutes
now if Jill cover 5 km distance and Scott cover 10 km distance
now we know that the formula of speed is given as
now we will have
speed of Jill
speed of Scott
so correct answer here is
<em>Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h.</em>
<em>#2</em>
distance travelled by each car is given as
now here it is given that
time taken by green car
time taken by yellow car
now we can find the speed of two cars
speed of green car
speed of yellow car
so correct answer will be
<em>The yellow car was faster. Yellow traveled at a speed of 50 mph while green was traveling at an average of 40 mph.</em>
Answer:
D) The spring will contract, raising the weight.
Explanation:
According to the statement there is current that will enter the current through the metal ions that it has in its stratum. The passage of the current will generate within the spring a magnetic field that travels in a loop. That is, while the upper part of the spring which is also that of the spring acts as a north pole, the lower part of the spring and the magnetic field will act as the south pole. The position of the poles will generate an opposition effect that will generate an attraction to each other which will generate a contraction in the spring and an increase in weight on it.
Answer:
The height of the bridge is 14.5
Explanation:
Given the following data
t = 2.9 seconds
g = +10m/s^2
Using the below formula
H = ut + 1/2gt^2
Since the initial velocity u = 0
Then, H = 1/2gt^2
H = 1/2 x 2.9 x 10
H = 2.9 x 10 / 2
H = 2.9 x 5
H = 14.5
The mass of the hoop is the only force which is computed by:F net = 2.8kg*9.81m/s^2 = 27.468 N
the slow masses that must be quicker are the pulley, ring, and the rolling sphere.
The mass correspondent of M the pulley is computed by torque τ = F*R = I*α = I*a/R F = M*a = I*a/R^2 --> M = I/R^2 = 21/2*m*R^2/R^2 = 1/2*m
The mass equal of the rolling sphere is computed by: the sphere revolves around the contact point with the table. So using the proposition of parallel axes, the moment of inertia of the sphere is I = 2/5*mR^2 for spin about the midpoint of mass + mR^2 for the distance of the axis of rotation from the center of mass of the sphere. I = 7/5*mR^2 M = 7/5*m
the acceleration is then a = F/m = 27.468/(2.8 + 1/2*2 + 7/5*4) = 27.468/9.4 = 2.922 m/s^2
