A. Bohr
It's the Answer to your Question
Answer:
Galileo Galilei was looking into a telescope and he realized we orbit around the sun and the moon orbits around us
Explanation:
Answer:
75.6J
Explanation:
Hi!
To solve this problem we must use the first law of thermodynamics that states that the heat required to heat the air is the difference between the energy levels of the air when it enters and when it leaves the body,
Given the above we have the following equation.
Q=(m)(h2)-(m)(h1)
where
m=mass=1.3×10−3kg.
h2= entalpy at 37C
h1= entalpy at -20C
Q=m(h2-h1)
remember that the enthalpy differences for the air can approximate the specific heat multiplied by the temperature difference
Q=mCp(T2-T1)
Cp= specific heat of air = 1020 J/kg⋅K
Q=(1.3×10−3)(1020)(37-(-20))=75.6J
The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s is 107 s
<h3>Data obtained from the question</h3>
The following data were obtained from the question given above:
- Initial velocity (u) = 11.1 Km/s
- Final velocity (v) = 11.7 Km/s
- Distance (s) = 1220 Km
- Time (t) =?
<h3>How to determine the time</h3>
The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s can be obtained as illustrated below:
s = (u + v)t / 2
Cross multiply
(u + v)t = 2s
Divide both sides by (u + v)
t = 2s / (u + v)t
t = (2 × 1220) / (11.1 + 11.7)
t = 2440 / 22.8
t = 107 s
Thus, the time taken for the spaceship to change its speed is 107 s
Learn more about speed:
brainly.com/question/680492
Learn more about velocity:
brainly.com/question/3411682
#SPJ1
Power is defined as rate of work done which means it is work done in 1 second of time
Now it is given that we have a horse that will give power 745.7 W
So it will do work of 745.7 J in 1 second of time
now if we wish to find the work done by horse in 0.55 s
so we can say
So it will do total work of 410.14 J in 0.55 s of time
