Answer:
Im not sure about Q1 but I'll help with Q2
9 =

8 =
![\sqrt[3]{512}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B512%7D%20)
14 =

2 =
![\sqrt[3]{8}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B8%7D%20)
4 =

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Answer:
Hence the new height is 3 times the original height .(h1=3h)
Step-by-step explanation:
Given:
A cone with has height and base with radius r .
To Find:
What is new height
Solution:
Consider as cone with height h base radius r, and volume v
Here given that only height changes for the cone i.e. r remains the unchanged or same or constant
The volume for a regular cone is given by ,

Here V is directly proportional to h i.ee pie ,3 and r being constant

i.e V/h=constant
V1 and h1 are new dimensions for new cone
V/h=V1/h1
Here V1=3V
So V/h=3V/h1
1/h=3/h1
i.e h1=3h
Hence the height is 3 times the original height .
Answer:
22-6
Step-by-step explanation:
there isnt a variable so the answer is 16
My work for your question
Answer:
There are 5000 mililitres in 5 litres
Therefore option A.
Hope u got the answer............