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3 years ago

Find the constant of proportionality for the table of values

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

3 0

The proportionality for the table values would be an increasing value of 1.5y for every X.

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diamong [38]

y=mx+b is the equation of a line;

m=slope , b= y-intercept

m=4 ; so we have : y=4x+b

We are give a set of points which it passes through, we can simply plug them in:

-2 = 4(3)+b (3 is the x and -2 is the y)

We get -2 = 12 +b .... -14=b

our final equation is : y=4x-14

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Write f(x)=8x^2-4x+11 in vertex form

Vlad [161]

Answer:

$f(x)=8(x-\frac{1}{4})^{2}+\frac{21}{2}$

$f(x)=8(x-0.25)^{2}+10.5$

Step-by-step explanation:

we have

$f(x)=8x^{2}-4x+11$

This is a vertical parabola open upward (because the leading coefficient is positive)

The vertex is a minimum

Convert to vertex form

Factor the leading coefficient

$f(x)=8(x^{2}-\frac{1}{2}x)+11$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$f(x)=8(x^{2}-\frac{1}{2}x+\frac{1}{16})+11-\frac{1}{2}$

$f(x)=8(x^{2}-\frac{1}{2}x+\frac{1}{16})+\frac{21}{2}$

Rewrite as perfect squares

$f(x)=8(x-\frac{1}{4})^{2}+\frac{21}{2}$ ----> equation in vertex form

$f(x)=8(x-0.25)^{2}+10.5$

The vertex is the point (0.25,10.5)

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