$f(x)=x^3e^{2x}\\\\f'(x)=(x^3e^{2x})'\qquad\text{use}\ (f\cdot g)'(x)=f'(x)g(x)+f(x)g'(x)\\\\=(x^3)'(e^{2x})+(x^3)(e^{2x})'\\\\\text{use}\ (x^n)'=nx^{n-1}\ \text{and}\ (e^x)'=e^x\ \text{and}\ f'[g(x)]=f'(g(x))\cdot g'(x)\\\\=3x^2e^{2x}+x^3e^{2x}\cdot2\\\\=\boxed{3x^2e^{2x}+2x^3e^{2x}}$

5 0

4 years ago

Dylan open a credit card account with $700 of available credit. Now that he has made some purchases, Dylan's account only has $5

Goshia [24]

Answer is: (B)

532 / 700 = 0.76 = 76%
therefore
532 = 76%

that's 24% missing aka a 24% decrease

a brainliest would be appreciated

3 0

3 years ago

Marc showed 7 with this addition sentence 7=3+3+1. Use marc’s way to show these odd numbers with addition sentences . 5=

Doss [256]

The answer is: 5=3+1+1

3 0

3 years ago