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Charra [1.4K]
2 years ago
9

What were the limitations of dobereiner's classification?​

Chemistry
1 answer:
Lubov Fominskaja [6]2 years ago
8 0
Limitations of dobereniers triads:

It failed to explain the triads of known elements(I.e all elements) and were only limited.
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What is electronic confriguration​
nataly862011 [7]

Answer:

In atomic physics and quantum chemistry, the electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals. For example, the electron configuration of the neon atom is 1s² 2s² 2p⁶, using the notation explained below.

Explanation:

3 0
3 years ago
For parts a & b below, derive only the initial value problem set up.
Otrada [13]

Answer:

Explanation:

From the given information:

Let y(t) be the amount of sugar in tank A at any time.

Then, the rate of change of sugar in the tank is given by:

\dfrac{dy}{dt}= (rate \ in ) - ( rate \ out )

The rate of the sugar coming into the tank is 0

\text{rate of sugar going out }= \dfrac{y(t) \ pound}{100}\times \dfrac{1 }{min} \\ \\ = \dfrac{y}{100} \ pound/min

So; \\ \\ \\ \dfrac{dy}{dt} = 0 - \dfrac{y}{100}  \\ \\ \implies \dfrac{dy}{y }= -\dfrac{dt}{100 } \\ \\ \implies dx|y| = -\dfrac{t}{100}+C  \\ \\  \implies e*{In|y|}= e^{-\dfrac{t}{100}+C} \\ \\ \implies y = Ce^{-\dfrac{t}{100}}

Initial amount of sugar = 25 Pounds

Now; y(0) = 25

25 = Ce⁰

C = 25

So;  y(t) = 25 e^{-\dfrac{t}{100}

Thus, the amount of sugar at any time t = \mathbf{25 e^{^{-\dfrac{t}{100}}}}

B) For tank B :

\dfrac{dy}{dt}= 1 - \dfrac{y}{50 } \\ \\ \dfrac{dy}{dt}= \dfrac{50-y}{50} \\ \\  \dfrac{dy}{50-y }= \dfrac{dt}{50}

8 0
3 years ago
Moles to mass<br> HELP PLEASE <br> 15 pts
MariettaO [177]

Explanation:

nose amigo, la verdad yo también tengo dificultades escolares muchísimas gracias, Dios te bendiga en otro idioma por cierto mi anime favorito es cowboy beboop

4 0
3 years ago
Kinetic energy and gravitational potential energy are both forms of which type
scoundrel [369]

Answer:

<em>C. Potential energy</em>

Explanation:

Kinetic energy and gravitational potential energy are both forms of potential energy. Potential energy is stored energy, when an object is not in motion it has stored energy. When an object is an motion it has kinetic energy. An object posses gravitational potential energy when it is above or below the zero height.

8 0
3 years ago
How much faster do ammonia (NH3) molecules effuse than carbon monoxide (CO) molecules? Enter the ratio of the rates of effusion.
andreyandreev [35.5K]

Answer:

The molecules of ammonia will effuse 1.28 times faster than carbon monoxide.

Explanation:

The kinetic molecular theory tells us that

Vrms = √(3RT/MW) where vrms is the root mean square velocity of an ideal gas

So vrms is inversely proportional to MW and so will be the rate of effusion. Comparing ammonia and co we have:

rate (NH3)/rate(CO) = √MWCO/√MWNH3 = √28.01/√17.03 = 1.28

rate(NH3) = 1.28 rate CO

5 0
3 years ago
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