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goldenfox [79]
3 years ago
10

A student began with a 3.12 g sample that contained their unknown and charcoal. After recrystallization the mass of dried crysta

ls recovered was 2.61 g. What was the percent recovery
Chemistry
1 answer:
likoan [24]3 years ago
4 0

The percent recovery would be 83.65%

<h3>What is Percent Recovery?</h3>

The percent recovery of a recrystallization reaction can be mathematically deduced as:

Percent recovery = recovered amount/amount of original sample x 100%

In this case, the recovered amount = 2.61 g, and the original amount of sample = 3.12. Thus:

Percent recovery = 2.61/3.12 x 100%

                           = 83.65%

More on recrystallization can be found here: brainly.com/question/4568753

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In the process of ionization, what is the relationship between the second ionization energy (I2) and the third ionization energy
dimulka [17.4K]
<span>The first ionization energy is the energy that is obligatory in order to eliminate the first electron from an atom(neutral) in the GAS phase
, the second ionization energy is defined as  the energy required to remove the second electron from an atom(+1 ion) in the GAS phase.
</span>the third ionization energy is the energy it takes to remove an electron from a 2+ ion. (That means that the atom has already lost two electrons, you are now removing the third.) 
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hope it helps</span>
4 0
4 years ago
in a sample of silcon 92.21% of the atoms have a mass of 27.98 amu, 4.70% have a mass of 28.98 amu and 3.09% have a mass of 29.9
oksano4ka [1.4K]

Answer: 28.1 amu

Explanation:

Mass of isotope 1 = 27.98 amu

% abundance of isotope 1 = 92.21% = \frac{92.21}{100}=0.9221

Mass of isotope 2 = 28.98 amu

% abundance of isotope 2 = 4.70% = \frac{4.70}{100}=0.047

Mass of isotope 3 = 29.97 amu

% abundance of isotope 2 = 3.09% = \frac{3.09}{100}=0.0309

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(27.98 )\times 0.922+(28.98)\times 0.047+(29.97)\times 0.0309]

A=28.1amu

Therefore, the average atomic mass of silicon is 28.1 amu

5 0
3 years ago
A dry soil sample has a volume of 500 mL. After 400 mL of water are added to the soil, the soil becomes saturated with 150 mL of
Lerok [7]
The Answer is 50. hope this helps
4 0
3 years ago
Use Q = mcAT
mr Goodwill [35]

Answer:

1).....for the specific heat capacity(c) of water is 4200kg/J°C..

....guven mass(m)=320g(0.32kg)

...change in temperature(ΔT) =35°C

from the formula

Q=mcΔT

Q=0.32Kg x 4200kg/J°C x 35°C

Q=47,040Joules

5 0
3 years ago
Which is NOT needed to START a wildfire.
ratelena [41]

Answer:

you are correct

Explanation:

6 0
3 years ago
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