Answer:
the efficiency of the Carnot engine is e=0 .5060 (50.96%)
Explanation:
The carnot cycle effifiency e is calculated through
e = W/Q₂
where
W= work
Q₂= heat absorbed
Q₁= heat exhausted
from an energy balance
W= Q₂ - Q₁ ( the proportion of the heat absorbed that was not released was converted to work)
therefore
e=(Q₂-Q₁)/Q₂ = 1 - Q₁/Q₂ = 1 - 51 J/104 J = 0.5060 (50.96%)
CH4 + O2 = CO2 + H2O - Chemical Equation Balancer.
Answer : The limiting reactant is 
Explanation : Given,
Mass of 
= 30.0 g
Mass of = 75.0 g
Molar mass of = 44 g/mole
Molar mass of = 32 g/mole
First we have to calculate the moles of and .
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 5 mole of react with 1 mole of
So, 2.34 moles of react with 
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.
Therefore, the limiting reactant is
Answer:
A) Charging by contact
Explanation:
Transfer of heat by direct contact, Heat energy is conducted from the hotter medium to the cooler medium
