All categories

2 years ago

Help help help help help

Mathematics

1 answer:

Akimi4 [234]2 years ago

3 0

Answer:

3 left; 1 down

Step-by-step explanation:

You can determine the translation by identifying corresponding points on the two figures and counting the grid squares between them.

Here Q is a translation of P by 3 squares to the left and 1 square down.

You might be interested in

Mathew goes to the movies over the weekend

Rufina [12.5K]

Answer:

23.125$

Step-by-step explanation:

you have to divide the total amount of money by the total amount of people 92.50$/4=23.125$

3 0

3 years ago

Read 2 more answers

A tobacco company claims that its best-selling cigarettes contain at most 40 mg of nicotine. The average nicotine content from a

tatuchka [14]

Answer:

$t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722$

$df=n-1=15-1=14$

$p_v =P(t_{(14)}>2.722)=0.0083$

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

Step-by-step explanation:

Information provided

$\bar X=42.6$ represent the average nicotine content

$s=3.7$ represent the sample standard deviation

$n=15$ sample size

$\mu_o =40$ represent the value to check

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We want to verify if the nicotine content of the cigarettes exceeds 40 mg , the system of hypothesis are:

Null hypothesis: $\mu \leq 40$

Alternative hypothesis: $\mu > 40$

The statistic for this case would be:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

And replcing we got:

$t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722$

The degrees of freedom are:

$df=n-1=15-1=14$

The p value would be:

$p_v =P(t_{(14)}>2.722)=0.0083$

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

6 0

3 years ago

A box has dimensions of 17 in Long 1.3 ft wide and 8 inches high what is the volume of the Box the formula for the volume is V=

algol13

17*1.3*8 = 176.8in.^3
Volume=176.8in.^3

6 0

3 years ago

Read 2 more answers

which set of numbers can represent the side lengths, in centimeters, of a right triangle?a. 8,12,15b. 10,24,26c. 12,20,25d. 15,1

Mama L [17]

Answer:

Step-by-step explanation:

Pythagorean theorem (applicable on right triangles only) says:

$a^{2}+b^{2}=c^{2}$

Where $a$ and $b$ are the two legs of the triangle and $c$ is the length of the hypotenuse [THE LONGEST SIDE].

<u>We can square each leg on the triangle and take the sum, if that is equal to the square of the longest side, we have a right triangle. Let's check for all of these.</u>

$8^{2}+12^{2}\\=64+144\\=208$