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enot [183]
2 years ago
8

If f(x) = one-half left-bracket x right-bracket, what is f(7.6)? 3 3.5 3.8 4

Mathematics
1 answer:
Anton [14]2 years ago
5 0

This is a method of substituting values into a given function. The value of the function f x is 7.6 is 3.8

<h3>Functions and values</h3>

Given the following function expressed as:

f(x) = 1/2(x)

We are to determine the value of f(7.6). Substitute x = 7.6 into the function as shown:

f(7.6) = 1/2(7.6)

f(7.6) = 7.6/2

f(7.6) = 3.8

Hence the value of the function f x is 7.6 is 3.8

Learn more on functions and values here:brainly.com/question/6561461

#SPJ4

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cestrela7 [59]

Answer:

5.5

Step-by-step explanation:

So, this is a simple factoring problem. The answer is 5.5(2x-1). So, heres how we get that answer.

So, factoring is basically breaking down the problem into smaller parts. So once we simplify the problem, we can factor it.

  • Simplify by combining like terms: 5x+6x= 11x and -2.5-3=-5.5
  • Now we have 11-5.5=?
  • so, we need to have (2x-1) in our answer because the problem asks for that in the answer.
  • We need to find a number that satisfies the equation and answer
  • so, 5.5(2x) is 11x, and 5.5(-1) is 5.5.
  • 5.5 satisfies the equation, therefore is the answer
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Read 2 more answers
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Dimas [21]
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so  \bf \begin{array}{lccclll}&#10;&amount&concentration&&#10;\begin{array}{llll}&#10;concentration\\&#10;amount&#10;\end{array}\\&#10;&-----&-------&-------\\&#10;\textit{70\% pure}&x&0.7&0.7x\\&#10;\textit{95\% pure}&y&0.95&0.95y\\&#10;-----&-----&-------&-------\\&#10;mixture&160&0.85&(160)(0.85)&#10;\end{array}

whatever "x" and "y" amounts are, we know, they must add up to 160 pints
thus  x + y = 160

now, whatever the concentrated amount of solute in the mixture, we know they must add up to 160*0.85 or 136

thus   0.7x + 0.95y = 136

thus    \bf \begin{cases}&#10;x+y=160\implies \boxed{y}=160-x\\&#10;0.7x+0.95y=136\\&#10;----------\\&#10;0.7x+0.95\left( \boxed{160-x} \right)=136&#10;\end{cases}

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what about "y"?  well, y = 160 - x
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