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solmaris [256]
2 years ago
11

Find the midpoint of the line segment with the given endpoints (4,-6), (9, 6)

Mathematics
1 answer:
kotegsom [21]2 years ago
4 0

Answer:

I think it's number 5 or (5,8)

Step-by-step explanation:

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I NEED THIS ASAP!!! PLEASE ANSWER FAST!!
Svetradugi [14.3K]

Answer:

C 6 months

Step-by-step explanation:

since u pay 20$ to sign up u can subtract that from 170=150

and then to find how many months the member payed divide by 25 since its how much u pay each month to get 6 months

8 0
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Find the slope of the line that passes through the
Lana71 [14]

Answer:

The slope of the line that passes through the points is 0 slope. That is B is the answer.

7 0
3 years ago
What value of n makes each statement true, pls include work
sammy [17]

Answer:

1. n=2

2. n=12

3. n=2

Step-by-step explanation:

1

12xy³/4xⁿy=3y²/x

12x²y³=12y³xⁿ (cross multiplied)

x²=xⁿ (cancelled out (12y³))

2=n

2

(-3a/2b⁴)³=-27a³/8bⁿ

-27a³/8b¹²=-27a³/8bⁿ (cubed left side)

-216a³bⁿ =-216a³b¹² (cross multiplied)

bⁿ=b¹² (cancelled out (-216a³))

n=12

3

(xy⁶/x⁵yⁿ)²=y⁸/x⁸

x²y¹²/x¹⁰y²ⁿ=y⁸/x⁸ (squared left side)

x²y¹²/x¹⁰y²yⁿ=y⁸/x⁸

y¹⁰/x⁸yⁿ=y⁸/x⁸ (simplified)

y¹⁰x⁸=x⁸yⁿy⁸ (cross multiplied)

y²=yⁿ (cancelled out (x⁸), simplified)

n=2

6 0
3 years ago
Factor of -2800 and -2
alekssr [168]

Answer:

isn't it just -2 it's the greatest common factor (GCF) of -2800 and -2

Step-by-step explanation:

4 0
3 years ago
A mayoral candidate in a large metropolitan area has hired you to take a poll to determine the proportion of registered voters w
sveticcg [70]

Answer:

The smallest sample size that will produce an interval with these specifications is 601.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

He would like you to report a 95% confidence interval with a margin of error no more than 0.04. What is the smallest sample size that will produce an interval with these specifications?

We have to find n for which M = 0.04.

We dont know the true proportion, so we use \pi = 0.5, which is when the smallest sample size needed will have it's largest value.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.04\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.04}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2

n = 600.25

Rounding up

The smallest sample size that will produce an interval with these specifications is 601.

6 0
3 years ago
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